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Andrew [12]
3 years ago
7

I am a 2 digit number the sum of my digits is 12. the ones digit is twice the tens digit? who am i?

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

84

Step-by-step explanation:

let a be the 1's digit and b the 10's digit, then

a = 2b ← twice the 10's digit, thus

sum = 2b + b = 12, that is

3b = 12 ( divide both sides by 3 )

b = 4

and a = 2b = 2 × 4 = 8

The 2 digit number is 84

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Solve for x " 1/6x+2/3x+4=x+2
storchak [24]
1/6x+4/6x+4=x+2
5/6x+4=x+2
x=12
8 0
3 years ago
Write an explicit formula for the geometric sequence below and use it to find the 9th term. 256, 64, 16, 4, . . .
Nastasia [14]

im doing this problem right now---

ok so a1=256 a2=64 a3=15 a4=4... find a9

the sequence divides by 1/4 every term

an=a1*r^n-1

an=(256)*(1/4)^n-1

replace n with 9

A9=(256)*(1/4)^9-1

A9=(256)*(1/4)^8

=(256)*(1/4)

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7 0
2 years ago
How to mentally subtract smaller numbers from bigger numbers?
Mamont248 [21]
Umm well ill show you how I do it so if it is 67 minus 72 I would subtract the tens spot first then I would do the ones it works for me and it is easy so I hope this helped ohand the answer is -5
3 0
3 years ago
Help me please!
telo118 [61]

Answer:

f^{-1}(6) = 50

Step-by-step explanation:

Given

f(x) = \sqrt{2x} - 4

Required

Find f^{-1}(6)

First, we calculate the inverse function

f(x) = \sqrt{2x} - 4

Express f(x) as y

y = \sqrt{2x} - 4

Swap the positions of x and y

x = \sqrt{2y} - 4

Solve for y: Add 4 to both sides

4 + x = \sqrt{2y} - 4+4

4 + x = \sqrt{2y}

Square both sides

(4 + x)^2 = 2y

Divide both sides by 2

y = \frac{(4 + x)^2}{2}

Express y as an inverse function

f^{-1}(x) = \frac{(4 + x)^2}{2}

Next, solve for: f^{-1}(6)

Substitute 6 for x

f^{-1}(6) = \frac{(4 + 6)^2}{2}

f^{-1}(6) = \frac{(10)^2}{2}

f^{-1}(6) = \frac{100}{2}

f^{-1}(6) = 50

7 0
3 years ago
3. In ΔABC, AB = 5 inches and BC = 3 inches. Which of the choices represents all possible values for AC, in inches?
Nonamiya [84]

Answer:

2< AC<8

Step-by-step explanation:

For a triangle to exits sum of two sides must always be greater than the the third side

⇒ AC<  AB+ BC =5+3=8 in

⇒AC<8 in

Also, the  difference of the two sides must be smaller than the length of third side

⇒ AC> | AB-BC| = |5-3| =2

AC> 2 in

therefore,  we can say  2< AC<8. Hence, AC can takes 3,4,5,6 values

4 0
3 years ago
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