1/6x+4/6x+4=x+2
5/6x+4=x+2
x=12
im doing this problem right now---
ok so a1=256 a2=64 a3=15 a4=4... find a9
the sequence divides by 1/4 every term
an=a1*r^n-1
an=(256)*(1/4)^n-1
replace n with 9
A9=(256)*(1/4)^9-1
A9=(256)*(1/4)^8
=(256)*(1/4)
A9=64^8
1/256 or a9= 0.00390625
Umm well ill show you how I do it so if it is 67 minus 72 I would subtract the tens spot first then I would do the ones it works for me and it is easy so I hope this helped ohand the answer is -5
Answer:
Step-by-step explanation:
Given
Required
Find 
First, we calculate the inverse function
Express f(x) as y
Swap the positions of x and y
Solve for y: Add 4 to both sides
Square both sides
Divide both sides by 2
Express y as an inverse function
Next, solve for:
Substitute 6 for x
Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
