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olga2289 [7]
2 years ago
6

Porfaaaaaaa ayudaaaaaaa

Mathematics
1 answer:
olchik [2.2K]2 years ago
8 0

The domain and the range of f(x) = -25x + 50 are the set of all real numbers

<h3>How to determine the domain and the range?</h3>

The function is given as:

f(x) = -25x + 50

The above function is a linear function.

All linear functions have their domain and range to be the set of all real numbers

Hence, the domain and the range of f(x) = -25x + 50 are the set of all real numbers

Read more about domain and range at:

brainly.com/question/1632425

#SPJ1

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A city park employee collected 1,850 cents in nickels, dimes, and quarters at the bottom of a wishing well. There were 30 nickel
makvit [3.9K]

Answer: there are 70 dimes and 40 quarters.

Step-by-step explanation:

A dime is 10 cents

A nickel is 5 cents

A quarter is 25 cents

Let x represent the number of dimes at the bottom.

Let y represent the number of quarters at the bottom.

The city park employee collected 1,850 cents in nickels, dimes, and quarters at the bottom of a wishing well. If there were 30 nickels, it means that

10x + 25y + 30 × 5 = 1850

10x + 25y = 1850 - 150

10x + 25y = 1700- - - - - - - - -1

There is a combined total of 110 dimes and quarters. It means that

x + y = 110

Substituting x = 110 - y into equation 1, it becomes

10(110 - y) + 25y = 1700

1100 - 10y + 25y = 1700

1100 + 15y = 1700

15y = 1700 - 1100

15y = 600

y = 600/15

y = 40

x = 110 - y = 110 - 40

x = 70

4 0
3 years ago
Describe the roots of the equation shown below.
Olegator [25]

Answer:

B. There is one real, double root

Step-by-step explanation:

For ax² + bx + c = 0, the discriminant is b² − 4ac.

If the discriminant is positive and a perfect square, there are two real, rational roots.

If the discriminant is positive and not a perfect square, there are two real, irrational roots.

If the discriminant is 0, there is one real, double root.

If the discriminant is negative, there are two complex roots.

Here, a = 64, b = -16, and c = 1.

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The discriminant is 0.  Therefore, there is one real, double root

5 0
4 years ago
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