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dsp73
2 years ago
14

Which expressions are equivalent to 3x

Mathematics
1 answer:
musickatia [10]2 years ago
7 0

x is powering both numbers so it can be outside the parenthesis.

We have given that 3^x.

<h3>What is the expression?</h3>

An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

The first one isn't an answer because 3^x is exponential while x^3 is a cubic function.

If you draw them you will see that they are very different.

B is correct because we can divide both numerator and denominator by 6 and we get 3^x.

C is not correct because x is not powering 3 so we cannot divide both by 6D is correct because 3^(x-1) is the same as

and when multiplied by 3 we get 3^x

3^x*3^(-1) = 3^x/3

E is not correct.

will understand after the explanation in DF is correct.

x is powering both numbers so it can be outside the parenthesis.

The question is incomplete the complete question is,

Which expressions are equivalent to the one below? Check all that apply.

3^x

A. x^3

B.(18/6)^x

C.18^x/3

D.3(3^(x-1))

E.3(3^(x+1))

F.18^x/6^x

To learn more about the  expression visit:

brainly.com/question/723406

#SPJ1

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2 years ago
Please explain your answer
MariettaO [177]

Answer:

e = -1/2

Step-by-step explanation:

4/3 = -6e - 5/3

transfer -6e to the right

4/3 = -5/3 -6e

Find the LCM of 3,3and 1

and their LCM is 3. So, divide all through by 3

3(4/3) = 3(-5/3) - 6e × 3

4 = -5 -18e

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9 = -18e

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9/ -18 = -18e/ -18

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3 years ago
Which equation represents the line that passes through the points (-5,2) and (9,0)
V125BC [204]

Step-by-step explanation:

<em>Given </em><em>points </em>

<em>(</em><em> </em><em>-</em><em>5</em><em> </em><em>,</em><em> </em><em>2</em><em>)</em><em> </em><em>and </em><em>(</em><em>9</em><em> </em><em>,</em><em> </em><em>0</em><em>)</em>

<em>First </em><em>calculating </em><em>slope(</em><em>m</em><em>)</em>

<em>=</em><em> </em><em>(</em><em> </em><em>y2 </em><em>-</em><em> </em><em>y1</em><em>) </em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>x2 </em><em>-</em><em> </em><em>x1</em><em>) </em>

<em>=</em><em> </em><em>(</em><em> </em><em>0</em><em>-</em><em>2</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>9</em><em>+</em><em>5</em><em>)</em>

<em>=</em><em> </em><em>-</em><em>2</em><em> </em><em>/</em><em> </em><em>1</em><em>4</em>

<em>=</em><em> </em><em>-</em><em>1</em><em>/</em><em>7</em>

<em>Now </em><em>The </em><em>equation </em><em>of </em><em>line </em><em>is </em><em>given </em><em>by </em>

<em>y </em><em>-</em><em> </em><em>y1 </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>-</em><em>2</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em><em>/</em><em>7</em><em> </em><em>(</em><em>x </em><em>+</em><em> </em><em>5</em><em>)</em>

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<em>x </em><em>+</em><em> </em><em>7y </em><em>-</em><em> </em><em>9</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

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