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Anika [276]
3 years ago
10

Help asap please !! Thank you soooo much t who ever helps.

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

A) 2 2/9

The answer would of course be positive because two negatives make a positive.

It would only be 6 4/9 if you added when here it states the obvious for you to subtract.

Hope this helped PLEASE MARK BRAINLIEST!!

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a rock band has 5 members and, 2/5 of the members play string instruments. Also, 0.4 of the members sing.Does the band have the
Bad White [126]
Convert 2/5 to a decimal and you get .4, or 40%. 40% of the band members also sing, so yes, the band has the same number of string instrument players and singers.
6 0
3 years ago
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A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
Based on the data set shown, which of the following is a true statement?
patriot [66]
The mean, median, and mode are equal to 1. So among the choices, the first one is correct - mean = mode

Mean - an <em>average </em>of the given set of number; to find this, add the numbers and divide it by 11 (the number of given data)
   = (-1 + -1 + 0 + 1 + 1 + 1 + 1 + 2 + 2 + 2 + 3) / 11
   = 1

Median - the <em>middle or center</em> of the given set; to find this, arrange the numbers in numerical order, then get the center or middle number as the median
   = <span>-1, -1, 0, 1, 1, 1, 1, 2, 2, 2, 3
   = [</span><span>-1, -1, 0, 1, 1,] <u>1</u>, [1, 2, 2, 2, 3]

Mode - is the value that occurs most of the time in the given set; so obviously <em>number 1 occurred four times</em> so 1 is our mode
</span>
3 0
3 years ago
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Simplify 4(5+t)+2t<br> Please explain steps taken
Digiron [165]

Answer:

6t+20

Step-by-step explanation:

4(5+t)+2t =

= 20+4t+2t =

= 20+6t =

= 6t+20

6 0
3 years ago
I need help with this i don’t understand
Phoenix [80]

Answer:

15

measure of third side is = 25^2 - 20^2

= 625 - 400

= 225

= √225

= 15

hope it helps

7 0
3 years ago
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