Step-by-step explanation:
<h3>#1)</h3>
As per the question, when the flow rate is negative, oil is moving into the small tank.
The large tank started with 600 gallons of oil. The recorded flow rate was - 4 gallons/ min.
That is, In one minute, 4 gallons of oil is moving from the large tank to the small tank.
Therefore, after 32 mins <u>1</u><u>2</u><u>8</u><u> </u><u>gals</u><u> </u><u>of</u><u> </u><u>oil</u><u> </u><u>has</u><u> </u><u>flown</u><u> </u><u>into</u><u> </u><u>the</u><u> </u><u>small</u><u> </u><u>tank</u><u>.</u>
<h3 /><h3> #2)</h3>
After 32 mins, the large tank lost 128 gallons of oil.
The remaining oil in the large tank = 600 - 128
=<u> 472 gallons </u>
Answer:
10
Step-by-step explanation:
As it could be inferred from the name, repeated measure design may be explained as experimental measures involving multiple (more than one) measures of a variable on the same observation, subject or participants which are taken at either various times or periodic intervals, different levels, different conditions. Hence, a repeated measurement taken with the same sample but under different treatment conditions. Therefore, since the measurement will be performed on a the same subjects(paired) , then the number of subjects needed will be 10. As it is this same samples that will be used for the other levels or conditions.
If you would like to solve 4.6 * x < - 15.64 for x, you can do this using the following steps:
4.6 * x < - 15.64 /4.6
x < - 15.64/4.6
x < - 3.4
The correct result would be x < - 3.4.
x³y²
For this case, the first thing you should know is the properties of the exponents.
Let's write the full fraction:
(1) / (x ^ 3 * y ^ 2)
We have that by power properties:
(1) / (x ^ 3 * y ^ 2) = x ^ -3 * y ^ -2
Therefore the equivalent numerator is:
x ^ -3 * y ^ -2
Answer:
x ^ -3 * y ^ -2
Answer:
6
Step-by-step explanation:
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