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Viefleur [7K]
3 years ago
7

the cost of a pencil is 25 cents more than the cost of an eraser. if the cost of 8 pencils and 10 erasers is 12.80 dollars, find

the cost of each

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
I hope this helps you

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Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x 2) f(x) = (x – 2)(x 2) f(x) = (x 1)(x – 2)
makvit [3.9K]

The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

<h3>How to determine the function?</h3>

For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:

(h,k) = (0,y)

A quadratic function is represented as:

f(x) = (x - h)^2 + k

So, we have:

f(x) = (x - 0)^2 + k

Evaluate

f(x) = x^2 + k

From the list of options, we have:

f(x) = (x - 2)(x + 2)

Expand

f(x) = x^2 - 4

Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)

Read more about vertex at:

brainly.com/question/18797214

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8 0
2 years ago
Joe has an ice cream stand. last week he spent $85 for ice cream and supplies. he earned $125. what was his profit?
Elodia [21]

Answer:

40 dollars

Step-by-step explanation:

Profit is what he earned minus his costs

Profit = 125 -85

Profit = 40

3 0
2 years ago
What’s a cows favorite type of math?
MA_775_DIABLO [31]
The answer is moo-ltiplication
7 0
3 years ago
Read 2 more answers
Analyze the diagram below and complete the instructions that follow. find sin angle C
tia_tia [17]

the answer is A ;

sin = opposite/ hypotenuse

= 24/ 26 ( we need to simplify it)

= 12/13

5 0
2 years ago
In a chess club the probability that Shaun will beat Mike is 3/8 .
romanna [79]

Answer:

\frac{10}{56} = 0.1786 probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So 1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8} probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So 1 - \frac{5}{7} = \frac{2}{7} probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786

\frac{10}{56} = 0.1786 probability that Shaun loses both games

3 0
3 years ago
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