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Amiraneli [1.4K]
2 years ago
13

Question 9 Eight wooden spheres with radii of 3 inches are packed snuggly into a cube-shaped box 12 inches on one side. The rema

ining space is filled with packing beads. What is the volume occupied by the packing beads
Mathematics
1 answer:
kobusy [5.1K]2 years ago
5 0
Answer is 823.2 cu.in.
Reason
For the sphere
We know V=4/3 TT r^3
Radius is 3
V=4/3 (3.14) 3^3
V= 4/3 (3.14) 27
V= 113.1 for each sphere
8 spheres x 113.1 = 904.8 cu.in.

For the cubed shaped box
We know v= length x width x height
V= 12 x 12 x 12
V = 1728 cu.in.

Now we take volume of box and subtract volume of spheres to get space filled by packing beads
1728 - 904.8 = 823.2 cu.in.
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What is the ratio of the number of cherry slices to the number of orange slices in the medium size bag of candy?
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Answer:

A

Step-by-step explanation:

There are 10 cherry slices and 40 orange slices in the medium bag. So, 10 to 40 simplifies to a ratio of 1 to 4.

5 0
3 years ago
Select the graph that represents the inequality <br><br> 2x + 3y &lt;= 6
Tanzania [10]
I think the answer is B, the one with a complete line and shaded to the bottom
8 0
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Find the factors of 9q²-45pq+8q-40p
Elina [12.6K]

Answer:

(x−5y)(9x+8)

Step-by-step explanation:

9x^2−45yx+8x−40y

Do the grouping 9x^2−45yx+8x−40y=(9x^2−45yx)+(8x−40y), and factor out 9x in the first and 8 in the second group.

9x(x−5y)+8(x−5y)

Factor out common term x−5y by using distributive property.

(x−5y)(9x+8)

5 0
3 years ago
What is the value of E(-1) n (3n+2)?
RoseWind [281]
<h3>Answer:  C) 6</h3>

====================================================

Explanation:

The weird looking E symbol is the greek uppercase letter sigma. It refers to a sum.

It tells us to add up terms in the form (-1)^n*(3n+2) where n is an integer ranging from n = 1 to n = 4.

------------------

If n = 1, then we have

(-1)^n*(3n+2) = (-1)^1*(3*1+2) = -5

Let A = -5 as we'll use it later.

------------------

If n = 2, then

(-1)^n*(3n+2) = (-1)^2*(3*2+2) = 8

Let B = 8 since we'll use this later as well

------------------

If n = 3, then

(-1)^n*(3n+2) = (-1)^3*(3*3+2) = -11

Let C = -11

-------------------

If n = 4, then

(-1)^n*(3n+2) = (-1)^4*(3*4+2) = 14

Let D = 14.

--------------------

We'll add up the values of A,B,C,D to get the final answer

A+B+C+D = -5+8+(-11)+14 = 6

This means that

\displaystyle \sum_{n=1}^{4}(-1)^n(3n+2) = 6

6 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

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Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

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