If a logarithm has a coefficient, then the coefficient can also be written as the exponent of the input of the logarithm. In other words, if you have the logarithm alog(x), that is equal to log(x^a). So the expression can be rewritten:
log(x^2)+log(y^3)
If tow logarithms of the same bases are added together that is equal to the logarithm of the product of the inputs of the two original logarithms. In other words, given log(x)+log(y), it can also be written as log(xy). So the expression can be combined into one logarithm:
log(x^2 * y^3)
Step-by-step explanation:
1. Use the Pythagorean theorem to solve for side KM:
- 16^2+KM^2=34^2
- 256+KM^2=1156
- KM^2=900
- KM=30
2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34
3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16
4. Sine is opposite over hypotenuse, so sine of M will be 16/34
5. KM=30, solved for in step 1.
hope this helps!!
Answer:
one solution, (-1,0)
Step-by-step explanation:
Since both y’s are negative you can combine them to make -6y=1 then you divide -6 on each Side to get y=6
