So we need to find the sum of the first 5 terms.
You have told me that the first term is 10 meters, and that r = 0.5 per term.
With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).
Plugging in the terms that we know...
s₅=10((1-0.5⁵)/(1-0.5))
s₅=10(0.96875/0.5)
s₅=10(1.9375)
s₅=19.375
With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.
Answer:
Step-by-step explanation:
<u>The ratio of corresponding sides of similar figures is same:</u>
- 3x/20 = (4x + 2)/(20 + 8)
- 3x/20 = (2x + 1) / 14
- 3x(14) = (2x + 1)(20)
- 42x = 40x + 20
- 2x = 20
- x = 10
Answer:
the students that brought a lunch box is 28
Step-by-step explanation:
The computation of the students that brought a lunch box is shown below:
= Entire school students × students that carry a lunch box ÷ entering students
= 84 students × 8 ÷ 24 students
= 28 students
Hence, the students that brought a lunch box is 28
X=2 because first you have to combine like terms. Than you have to bring the Varible on one side. Finally you solve for the Varible and you get the answer2.
Answer:
(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.
Step-by-step explanation:
Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.
Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.
Test statistic (t) = (sample mean - population mean) ÷ sd/√n
sample mean = 3.24 minutes
population mean = 3.3 minutes
sd = 0.4 minutes
n = 62
degree of freedom = n - 1 = 62 - 1 = 71
significance level = 0.08
t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2
The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654
Conclusion:
Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.
