Write a beta decay equation for the
1 answer:
The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above will be,
The reduction in the number of radionuclides per unit time is the rate of decay.
The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has 104 protons and 183 neutrons.
Atomic weight = 104+183 = 287
Atomic number = 104
The beta decay equation is;
Hence the beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above.
To learn more about the rate of decay refer to the link;
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Answer:
New pressure of the gas increases by 26.5% with respect to initial pressure, new volume decreases 27% with respect to initial volume and new temperature decreases 8% with respect to initial volume.
Explanation:
If we assume the gas is a perfect gas we can use the perfect gas equation:
- For Isothermal process:
(1)
Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:
(2)
- For Isobaric process:
(3)
Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:
(4)
- For Isochoric process:
(5)
Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:
(6)
So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:
This is, the new pressure of the gas increases by 26.5% with respect to initial pressure.
Similarly, we have V3=V4, V3=0.8*V2 and V1=1,1*V2:
so the final volume decreases 27% with respect to initial volume.
T4=1,15*T3, T3=0.8*T2 and T1=T2:
The new temperature decreases 8% with respect to initial volume.