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GenaCL600 [577]
3 years ago
7

Which describes energy changes during nuclear fission?

Physics
2 answers:
vodka [1.7K]3 years ago
5 0
A very large amount of energy is produced from a very small mass. hoped this helped!!!
AleksAgata [21]3 years ago
5 0

The correct answer is a large amount of energy is produced from a series  of chemical reactions. I hope this helped.

If this helped please mark Brainiest

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What refers to a soils ability to transmit water
Keith_Richards [23]

Answer:

Permeability is also called as hydraulic conductivity, which refers to the ability of a soil to conduct water. ... Composition is of four basic categories: water, air, organic matter and minerals.

Explanation:

idk, i knew a bit and looked it up to make sure i was correct.

6 0
3 years ago
Two tiny beads are 25 cm apart with no other charges or fields present. Bead A carries 10 µC of charge and bead B carries 1 µC.
steposvetlana [31]
The electric forces on both beads are equal.
3 0
3 years ago
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Select the correct answer.<br> Which type of energy is thermal energy a form of
elena-s [515]
Kinetic energy. thermal energy (a low form of energy ) is a form of kinetic energy as it is produced as a result of motion of particles either if they vibrate at their position or they move along longer paths. Motion produces friction or resistance which leads to excitation and thus the heat is produced. The higher the motion of the particles, the higher would be the thermal energy.
7 0
2 years ago
An imaginary line perpendicular to a reflecting surface is called ____refrac_____.
umka2103 [35]
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4 0
3 years ago
A light bulb dissipates 100 Watts of power when it is supplied a voltage of 220 volts.
ycow [4]

Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

Answer:

a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

P = VI

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

I = \frac{P}{V}  \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

V = IR

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega

Therefore, the resistance of the bulb is 484 Ω

3 0
3 years ago
Read 2 more answers
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