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2 years ago

A car is accelerating when it is:________.

Physics

1 answer:

Jet001 [13]2 years ago

6 0

Answer: A car is accelerating when it is traveling on a straight uphill road at 30 miles per hour.

Explanation:

Acceleration is the change in velocity of an object with respect to time. For a body to accelerate, its velocity must be changing at every time interval. According to option a and c, the velocity of the body is constant during the journey but the time is changing. A body with constant velocity possesses a zero acceleration.

A car travelling on a straight up hill possesses velocity change at each time interval. Since the car is on a slope, its shows its acceleration is changing.

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The scientific method can easily be misinterpreted as ___________. Question 1 options: a great magical trick, or slide of hands,

evablogger [386]

Answer:

I think the answer is

a "cookbook" recipe for performing scientific investigations

Explanation:

5 0

2 years ago

Read 2 more answers

In a nuclear physics experiment, a proton (mass 1.67×10^(−27)kg, charge +e=+1.60×10^(−19)C) is fired directly at a target nucleu

Arte-miy333 [17]

The given question is incomplete. The complete question is as follows.

In a nuclear physics experiment, a proton (mass $1.67 \times 10^(-27)$ kg, charge +e = $+1.60 \times 10^(-19)$ C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed $2.50 \times 10^6$ m/s. The proton comes momentarily to rest at a distance $5.31 \times 10^(-13)$ m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are $5.31 \times 10^{-13}$ m apart?

Explanation:

The given data is as follows.

Mass of proton = $1.67 \times 10^{-27}$ kg

Charge of proton = $1.6 \times 10^{-19} C$

Speed of proton = $2.50 \times 10^{6} m/s$

Distance traveled = $5.31 \times 10^{-13} m$

We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.

$(K.E + P.E)_{initial}$ = $(K.E + P.E)_{final}$

$(\frac{1}{2} m_{p}v^{2}_{p}) = (\frac{kq_{p}q_{t}}{r} + 0)$

where, $\frac{kq_{p}q_{t}}{r} = U = Electric potential energy$

U = $(\frac{1}{2}m_{p}v^{2}_{p})$

Putting the given values into the above formula as follows.

U = $(\frac{1}{2}m_{p}v^{2}_{p})$

= $(\frac{1}{2} \times 1.67 \times 10^{-27} \times (2.5 \times 10^{6})^{2})$

= $5.218 \times 10^{-15} J$

Therefore, we can conclude that the electric potential energy of the proton and nucleus is $5.218 \times 10^{-15} J$ .

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3 years ago

What is night vision pls explain in long answers use<br> can use google

bulgar [2K]

Answer:

Night vision is the ability to see in low-light conditions. Whether by biological or technological means, night vision is made possible by a combination of two approaches: sufficient spectral range, and sufficient intensity range.

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3 years ago

De donde eres responde y te doy corona

irakobra [83]

soy de texas, united states

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2 years ago

Old-fashioned pendulum clocks are powered by masses that need to be wound back to the top of the clock about once a week to coun

Andreyy89

Answer:

Energy, E = 178.36 J

Explanation: