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3 years ago

A car is accelerating when it is:________.

Physics

1 answer:

Jet001 [13]3 years ago

6 0

Answer: A car is accelerating when it is traveling on a straight uphill road at 30 miles per hour.

Explanation:

Acceleration is the change in velocity of an object with respect to time. For a body to accelerate, its velocity must be changing at every time interval. According to option a and c, the velocity of the body is constant during the journey but the time is changing. A body with constant velocity possesses a zero acceleration.

A car travelling on a straight up hill possesses velocity change at each time interval. Since the car is on a slope, its shows its acceleration is changing.

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Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial p

Archy [21]

Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

According to the question

Terrestrial Planets:

They belongs to a class of planets that are like the earth

Geological destiny :

Geology is biological destiny: Whatever minerals land or are deposited in a place determine what or who can make a living there millions of years later

Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny

i.e

The size of terrestrial planet is one of the factors to play the most important role in a terrestrial planet's geological destiny

which determines how long the planet can retain internal heat, which drives geological activity because Smaller worlds cool off faster and harden earlier .

Hence, Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

To know more about terrestrial here:

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6 0

2 years ago

For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici

lord [1]

Answer:

Temperature of the hot reservoir is 1540K

Explanation:

$E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35 (convert 35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation 1)20%=1-{T_c}/{T_h}$

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

5 0

3 years ago

Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

7 0

4 years ago

A mass attached to a spring oscillates with a period of 22 sec. After 22 kg are added, the period becomes 33 sec. Assuming that

polet [3.4K]

Answer:

Mass of 17.854 kg is only attached to the spring

Explanation:

We have given time period in first case is 22 sec

Let initially mass is m

After 22 kg are added the period becomes 33 sec

Time period of spring mass system is

$T=2\pi \sqrt{\frac{m}{k}}$ , here m is mass and k is spring constant

From the relation we can see that

$\frac{T_1}{T_2}=\sqrt{\frac{m}{m+22}}$

$\frac{22}{33}=\sqrt{\frac{m}{m+22}}$

Squaring both side

$0.444={\frac{m}{m+22}}$

$0.444m+9.777=m$

m = 17.584 kg

So mass of 17.854 kg is only attached to the spring

7 0

3 years ago

B Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring, and

zubka84 [21]

Answer:

Minerals must be solid, have an orderly atomic structure, have a recognized chemical composition, be naturally occurring and <u>inorganic in origin</u>.

Explanation:

6 0

3 years ago