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3 years ago

2. A projectile is launched at a speed of 35 m/s and an angle of 40 above the horizontal.

Physics

2 answers:

IrinaVladis [17]3 years ago

6 0

Answer:

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PolarNik [594]3 years ago

5 0

Answer:

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Explanation:

nsvavsvahshwhwbwgeg

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Determine whether or not each of the following statement is true. If a statement is true, prove it. If the statement is false, p

Studentka2010 [4]

Answer:

True

Explanation:

This is a representation of Gauss law.

Gauss’s law does hold for moving charges, and in this respect Gauss’s law is more general than Coulomb’s law. In words, Gauss’s law states that: The net outward normal electric flux through any closed surface is proportional to the total electric charge enclosed within that closed surface. The law can be expressed mathematically using vector calculus in integral form and differential form, both are equivalent since they are related by the divergence theorem, also called Gauss’s theorem.

8 0

3 years ago

a block of wood has a length of 4 cm a width of 5 cm and a height of 10 cm what is the volume of the wood

geniusboy [140]

Volume= Length X width X height.

Plug in the values for each and solve for the volume.

V= (L)(W)(H)

V=(4cm)(5cm)(10cm).

8 0

3 years ago

Ice does not need to melt into liquid water before it can return to the atmosphere as water vapor.

Nuetrik [128]

That only happens when the temperature is below freezing and the air around the ice is dry.

6 0

3 years ago

Steve and Jose drove Jose's car to the beach during Spring Break. The 495 kilometer drive took them 8 hours and 30 minutes. What

Vaselesa [24]

Answer:

58.24 Km/h.

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 495 Km

Time (t) = 8 h 30 mins

Speed (S) =?

Next, we shall express 8 hours 30 mins to hours.

We'll begin by convert 30 mins to hour.

60 mins = 1 h

Therefore,

30 mins = 30 mins × 1 h/ 60 mins

30 mins = 0.5 hour.

Thus,

8 h 30 min = 8 + 0.5 = 8.5 hours

Speed is define as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the speed as shown below:

Distance (d) = 495 Km

Time (t) = 8.5 hour

Speed (S) =?

Speed = Distance /time

Speed = 495 Km / 8.5 hour

Speed = 58.24 Km/h

Thus, the speed is 58.24 Km/h.

3 0

3 years ago

A bug is 12 cm from the center of a turntable that is rotating with a frequency of 45 rev/min . What minimum coefficient frictio

Agata [3.3K]

Answer:

The minimum coefficient of friction is 0.27.

Explanation:

To solve this problem, start with identifying the forces at play here. First, the bug staying on the rotating turntable will be subject to the centripetal force constantly acting toward the center of the turntable (in absence of which the bug would leave the turntable in a straight line). Second, there is the force of friction due to which the bug can stick to the table. The friction force acts as an intermediary to enable the centripetal acceleration to happen.

Centripetal force is written as

$F_c = m\frac{v^2}{r}$

with v the linear velocity and r the radius of the turntable. We are not given v, but we can write it as

$v = r\omega$

with ω denoting the angular velocity, which we are given. With that, the above becomes:

$F_c = m\frac{v^2}{r}=m\omega^2 r$

Now, the friction force must be at least as much (in magnitude) as Fc. The coefficient (static) of friction μ must be large enough. How large?

$F_r=\mu mg \geq m\omega^2 r = F_c\implies\\\mu \geq \frac{\omega^2 r}{g}$

Let's plug in the numbers. The angular velocity should be in radians per second. We are given rev/min, which can be easily transformed by a factor 2pi/60:

$\frac{1 rev}{1 min}\cdot\frac{\frac{2\pi rad}{rev}}{\frac{60s}{1 min}}=\frac{2\pi}{60}\frac{rad}{s}$

and so 45 rev/min = 4.71 rad/s.

$\mu \geq \frac{\omega^2 r}{g}=\frac{4.71^2\frac{1}{s^2}\cdot 0.12m}{9.8\frac{m}{s^2}}=0.27$

A static coefficient of friction of at least be 0.27 must be present for the bug to continue enjoying the ride on the turntable.

3 0

2 years ago