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Advocard [28]
2 years ago
8

Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is

Physics
1 answer:
Ipatiy [6.2K]2 years ago
6 0

Its really hurts

Explanation:

Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is

2.0 C. Charge C, which is 2.0 C, is located between them and is in

electrostatic equilibrium. How far from charge A is charge C?

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You have a motion security light by your door cat runs across the in the light turns on what is the input of the system and what
Neporo4naja [7]
A motion security line is a system that is used to detect motion.
The input for the system is MOTION and the output is LIGHT. That is, when the system detects motion it switch on light.
Remember, an Input is the information that was inserted into a system while the output is the result of the processed information.
5 0
2 years ago
Suppose that a pendulum has a period of
Yakvenalex [24]

Explanation:

period of pendulum = time taken for 1 oscillation = time taken for 1 complete back and forth vibration

q1 ans is given in question its 1.5 sec

q2 ans is 1.5 sec longer than 1 sec period

4 0
2 years ago
Pads are used in athletic activities to __________.
Anit [1.1K]
Absorb kinetic energy and soften potentially damaging blows.
7 0
3 years ago
At a certain harbor, the tides cause the ocean surface to rise and fall a distance d (from highest level to lowest level) in sim
OleMash [197]

Answer:

1.869 hours

Explanation:

T = Time period = 11.1 h

Angular frequency is given by

\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{11.1}\\\Rightarrow \omega=0.566\ rad/h

The distance moved from highest to lowest level is given by

d=2x_{m}\\\Rightarrow x_m=\frac{d}{2}\\\Rightarrow x_m=0.5d

At the ocean surface x_m=0.25d

x=x_mcos(\omega t+\phi)

\phi = Phase constant = 0 as clock is started at x_0=x_m

0.25d=0.5dcos(0.56t)\\\Rightarrow cos(0.56t)=\frac{0.25}{0.5}\\\Rightarrow 0.56t=cos^{-1}0.5\\\Rightarrow t=\frac{1.047}{0.56}\\\Rightarrow t=1.869\ h

The time taken for the water to fall the distance is 1.869 hours

7 0
2 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.80×106 N , one at an angle 14.0 ∘ west of north,
Leviafan [203]

Answer:

W = 1,049 10⁹ J

Explanation:

Work is defined by the relation

         W = F. d = F d cos θ

where tea is the angle between the forces and the displacement.

The total work is the sum of the work of each tug.

Tug 1

       W₁ = F d cos θ₁

 

the angle measured from the positive side of the x-axis is

       θ₁ = 14 + 90 = 104º

           

tugboat 2

             W₂ = F d cos θ₂

             θ₂ = 14

we substitute

             W = F d cos θ₁ + F d cos θ₂

             W = F d (cos θ₁ + cos θ₂)

               

let's calculate

             W = 1.80 10⁶  800 (cos 104 + cos 14)

             W = 1,049 10⁹ J

5 0
2 years ago
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