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1 year ago

9

What is the solution to the equation below? √x+3-x-3 Will give brainliest

1 answer:

kati45 [8]1 year ago

3 0

Answer:

9 Square +3-×-3 =6

6-3=12

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Help please i don’t understand and this is do today :/!!

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Answer:

5.8

Step-by-step explanation:

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3 years ago

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A church group ordered a total of 22

blagie [28]

Answer:

the group bought 10 burger and 12 drinks

Step-by-step explanation:

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2 years ago

Given: <br><br> ∆SPM, PK⊥ SM<br><br> SP = 25, SM = 28, PK = 9<br><br> Find: m∠S, m∠M, PM

nevsk [136]

Answer:

∠S = 21.10°

∠M = 79.45°

PM = 9.16

Step-by-step explanation:

Here Pythagorean theorem and trigonometry suffice to solve our problem.

From the Pythagorean theorem we get:

$KM^2+9^2=PM^2$ and

$(25-KM)^2+9^2=25^2.$

We solve for $KM$ in the second equation and get:

$(25-KM)=\sqrt{25^2-9^2}$

$\therefore KM=25-\sqrt{25^2-9^2} =\boxed{1.68}$

Now since

$SK+KM=25\\\\ SK=\boxed{23.32}$

Therefore

${\angle}S=Tan^{-1}(\frac{PK}{SK}) = Tan^{-1}(\frac{9}{23.32})=21.10^o$

and

${\angle}M=Tan^{-1}(\frac{PK}{KM}) = Tan^{-1}(\frac{9}{1.68})=79.45^o.$

And finally again from the Pythagorean theorem:

$PM^2=PK^2+KM^2=9^2+1.68^2$

$\therefore PM=\sqrt{9^2+1.68^2} =9.16.$

Thus,

∠S = 21.10°

∠M = 79.45°

PM = 9.16.

7 0

3 years ago

Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

<em>The perimeter is </em> $18 + 3\sqrt 5 + 3\sqrt 2$ <em>units</em>
<em>The area of the sanctuary is 27 square units</em>

We have:

$A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)$

<u>Perimeter</u>

See attachment for the layout of the sanctuary

$BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

From the attachment, the sides are

<em>AB, BF, FC, CD, DE and EA</em>

Start by calculating the length of each side using the following distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}$

So, we have:

$AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3$

$BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5$

$FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2$

$CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7$

$DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3$

$EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5$

So, the perimeter (P) is:

$P = AB + BF + FC + CD + DE + EA$

$P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5$

$P = 18 + 3\sqrt 5 + 3\sqrt 2$

<em>Hence, the perimeter is </em> $18 + 3\sqrt 5 + 3\sqrt 2$ <em>units</em>

<u />

<u>Area</u>

To calculate the area, we need to divide the sanctuary into three.

<em>Triangle ABF</em>
<em>Triangle EFA</em>
<em>Trapezium CDEF</em>

The area of ABF is:

$Area = \frac 12 \times AB \times FA$

Where:

$AB = 3$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

$Area = \frac 12 \times 3 \times 3$

$Area = \frac 92$

The area of EFA is:

$Area = \frac 12 \times EF \times FA$

Where:

$FA = 3$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

So:

$Area = \frac 12 \times 4 \times 3$

$Area = 6$

The area of CDEF is:

$Area = \frac 12(CD + EF) \times DE$

Where

$CD = 7$

$EF = 4$

$DE = 3$

So, we have:

$Area = \frac 12 (7 + 4) \times 3$

$Area = \frac 12 \times 11 \times 3$

$Area = \frac {33}2$

So, the area of the sanctuary is:

$Area = \frac 92 + 6 + \frac {33}2$

$Area = \frac {9 +12 + 33}2$

$Area = \frac {54}2$

$Area = 27$

<em>Hence, the area of the sanctuary is 27 square units</em>

Read more about areas and perimeters at:

brainly.com/question/11957651

8 0

2 years ago

Am I d u m b or what?

jok3333 [9.3K]

Answer:

w=3

Step-by-step explanation:

3w= 9

divide 3 on both sides

3/3 = 9/3

3/3 cancels out

9/3 = 3

8 0

2 years ago

Read 2 more answers