<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
Answer:
A) y = x^2 -1
B) -y = 2x^2 +1 We multiply B) by -1
B) y = -2x^2 -1
We can then say x^2 -1 = -2x^2 -1
3 x^2 = 0
x = 0
************* Double-Check: ******************
Equation A) y = -1 and
Equation B) y = -1
Step-by-step explanation:
Answer:
x=-85
Step-by-step explanation:
Answer:
Step-by-step explanation:
"The graph of f(x) is a horizontal compression of the graph of the parent function" is true; the graph will appear to be narrower than that of y = |x|. I would prefer to state "the graph of f(x) exhibits vertical stretching of the original (parent) function graph."
