Do the ch3f molecules appear to attract each other much? briefly describe their interaction.
1 answer:
Neither attract much nor allows it be free.
How the molecules behave in such way?
Because fluorine has a higher electronegativity than carbon and hydrogen, CH3F possesses a non-zero dipole moment. As a result, fluorine draws a partial negative charge whereas other atoms (such as carbon or hydrogen) draw a partial positive charge, leading to a non-zero dipole moment in CH3F. Lewis' structure, CH3F, is made up of one carbon atom, three hydrogen atoms, and one fluorine atom. Carbon is the key atom in the CH3F lewis structure because it is the least electronegative. The CH3F lewis dot structure consists of 3 lone pairs and a total of 4 bound pairs.
Properties of CH3F
- It molar mass is 34.03 g/mol.
- The density of CH3F is 1.4397 g/L and 0.557 g/cm³ at saturated pressure and temperature.
- The melting point of CH3F is -137.8ºC and the Boiling point is -78.4ºC.
- Its vapor pressure is 3.3 MPa.
- Its IUPAC name is Fluoromethane.
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Answer:
The answer to the question is
The temperature at which the vapor pressure will be 5.00 times higher than it was at 331 K is 353.0797 K.
Explanation:
To solve the question, we make use of the Clausius-Clapeyron equation as follows
Where P₁ = Initial pressure
P₂ = Final pressure
T₁ = Initial temperature = 331 K
T₂ = Final temperature
dvapH = ΔvapH = Heat of vaporization = 70.83 kJ / mol.
R = Universal gas constant = 8.3145. J K⁻¹ mol⁻¹
We are required to find the temperature when P₂ = 5 × P₁
Therefore we have
=
or T₂ =
= 353.0797 K
The vapor pressure be 5.00 times higher than it was at 331 K when the temperature is raised to 353.0797 K.