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WARRIOR [948]
2 years ago
13

Do the ch3f molecules appear to attract each other much? briefly describe their interaction.

Chemistry
1 answer:
suter [353]2 years ago
7 0

Neither attract much nor allows it be free.

How the molecules behave in such way?

Because fluorine has a higher electronegativity than carbon and hydrogen, CH3F possesses a non-zero dipole moment. As a result, fluorine draws a partial negative charge whereas other atoms (such as carbon or hydrogen) draw a partial positive charge, leading to a non-zero dipole moment in CH3F. Lewis' structure, CH3F, is made up of one carbon atom, three hydrogen atoms, and one fluorine atom. Carbon is the key atom in the CH3F lewis structure because it is the least electronegative. The CH3F lewis dot structure consists of 3 lone pairs and a total of 4 bound pairs.

Properties of CH3F

  • It molar mass is 34.03 g/mol.
  • The density of CH3F is 1.4397 g/L and 0.557 g/cm³ at saturated pressure and temperature.
  • The melting point of CH3F is -137.8ºC and the Boiling point is -78.4ºC.
  • Its vapor pressure is 3.3 MPa.
  • Its IUPAC name is Fluoromethane.

Know more about carbon here:

brainly.com/question/3049557

#SPJ4

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Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2 
∴ the emprical formula C3H8O2
           



6 0
3 years ago
_______________________________________________
AnnyKZ [126]

Answer:

Answer:

Already answered brainly.com/question/845321563

Explanation:

8 0
3 years ago
PLEASE HELP ITS DUE TODAY
dimulka [17.4K]

Answer:

2nd one and last one

Explanation:

im just that smart

8 0
3 years ago
Read 2 more answers
B) All atoms contain<br>charged electrons.<br>​
andrey2020 [161]

Answer:

b) All atoms contain

charged electrons.

Explanation:

8 0
3 years ago
A tank at is filled with of sulfur tetrafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal g
dangina [55]

The question is incomplete, the complete question is:

A 7.00 L tank at 21.4^oC is filled with 5.43 g of sulfur hexafluoride gas and 14.2 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas. Round each of your answers to significant digits.

<u>Answer:</u> The mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For sulfur hexafluoride:</u>

Given mass of sulfur hexafluoride = 5.43 g

Molar mass of sulfur hexafluoride = 146.06 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfur hexafluoride}=\frac{5.43g}{146.06g/mol}=0.0372mol

  • <u>For sulfur tetrafluoride:</u>

Given mass of sulfur tetrafluoride = 14.2 g

Molar mass of sulfur tetrafluoride = 108.07 g/mol

Putting values in equation 1, we get:

\text{Moles of sulfur tetrafluoride }=\frac{14.2g}{108.07g/mol}=0.1314mol

Total moles of gas in the tank = [0.0372+ 0.1314] mol = 0.1686 mol

Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

\chi_A=\frac{n_A}{n_A+n_B} .....(2)

where n is the number of moles

Putting values in equation 2, we get:

\chi_{SF_6}=\frac{0.0372}{0.1686}=0.221

\chi_{SF_4}=\frac{0.1314}{0.1686}=0.779

Hence, the mole fraction of sulfur hexafluoride is 0.221 and that of sulfur tetrafluoride is 0.779

7 0
3 years ago
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