Answer:

Explanation:
Equation for the heterogeneous system is given as:
⇄

The concentrations and pressures at equilibrium are:
![[A] = 9.68*10^{-2}M](https://tex.z-dn.net/?f=%5BA%5D%20%3D%209.68%2A10%5E%7B-2%7DM)

![[C]=14.64M](https://tex.z-dn.net/?f=%5BC%5D%3D14.64M)
![[D]=10.11M](https://tex.z-dn.net/?f=%5BD%5D%3D10.11M)

If we convert both pressure into bar; we have:



1 torr = 0.001333 bar

![K=\frac{[P_E]^3}{[A]^2[P_B]^3}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_E%5D%5E3%7D%7B%5BA%5D%5E2%5BP_B%5D%5E3%7D)


Answer:
8 mol
Explanation:
Step 1: Calculate the mass of PtCl₄ in the sample
10.00 grams of a sample of hydrated PtCl₄ are heated and lose 3.00 g of water. The mass of PtCl₄ is:
mPtCl₄ = 10.00 g - 3.00 g = 7.00 g
Step 2: Calculate the moles corresponding to 7.00 g of PtCl₄ and 3.00 g of H₂O
The molar mass of PtCl₄ is 336.9 g/mol.
7.00 g × 1 mol/336.9 g = 0.0208 mol
The molar mass of H₂O is 18.02 g/mol.
3.00 g × 1 mol/18.02 g = 0.166 mol
The molar ratio of H₂O to PtCl₄ is:
0.166 mol H₂O/0.0208 mol PtCl₄ ≈ 8 mol H₂O/ 1 mol PtCl₄
Answer:
Following laboratory safety guidelines minimizes the chance of lab accidents.
Explanation:
Answer:
3 significant figures that is 9,7 and 2
A proton is about 1835 times more massive than an electron.