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raketka [301]
3 years ago
8

I have a few absolute value questions 20 POINTS AND BRAINLIEST TO THE RIGHT ANSWER

Mathematics
2 answers:
rjkz [21]3 years ago
3 0
1) 3
2) 8
3)10
4)-4
Hope this helped
Dovator [93]3 years ago
3 0
For absolute value,
|x| = x
|-x| = x
It is the distance from 0, for example, 2 is 2 units away from 0, and so is -2.

1) 3
2) 8
3) 10
4) 4
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Which of the following shows as a mixed number and as an improper fraction?
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There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

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3 years ago
Find two numbers with a sum of 20 and a difference of 14.
Alekssandra [29.7K]
The anwser is 17 and 3. 17+3=20, and the difference is 14!
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