Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
AB = 12
Step-by-step explanation:
Since the triangle is isosceles, the sides AB and BC are congruent. Then you have ...
4x = 2x+6
2x = 6 . . . . . . subtract 2x
4x = 12 . . . . . .multiply by 2
The side AB has length 12.
Number 3 is 9 not negative 10
(5-2/x)/4-3/x^2
after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3
now u can solve it
