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tangare [24]
2 years ago
11

What is an equation for the line parallel to y = −x + 2 going through the point (−3, −5)?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
7 0

The equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8

<h3>Equation of a line</h3>

The equation of a line in point slope form is expressed as:

y - y1 = m(x-x1)

Given the equation y = -x + 2, the slope of the line parallel to the line is -1

Substitute the slope and point (-3, -5)

y -(-5) = -1(x - (-3))

y+5 = -(x + 3)

y+5 =-x - 3

y = -x - 3 - 5

y = -x - 8

Hence the equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8

Learn more on equation of a line here: brainly.com/question/18831322

#SPJ1

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a.

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

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Approximate value (rounded to nearest tenth):  24\sqrt{3} =41.6

b.

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1

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Step-by-step explanation:

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