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tangare [24]
2 years ago
11

What is an equation for the line parallel to y = −x + 2 going through the point (−3, −5)?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
7 0

The equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8

<h3>Equation of a line</h3>

The equation of a line in point slope form is expressed as:

y - y1 = m(x-x1)

Given the equation y = -x + 2, the slope of the line parallel to the line is -1

Substitute the slope and point (-3, -5)

y -(-5) = -1(x - (-3))

y+5 = -(x + 3)

y+5 =-x - 3

y = -x - 3 - 5

y = -x - 8

Hence the equation for the line parallel to y = −x + 2 going through the point (−3, −5) is y = -x - 8

Learn more on equation of a line here: brainly.com/question/18831322

#SPJ1

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Let T:R²-&gt;R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)
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Answer:

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We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

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