All categories

4 years ago

Corrine wrote temperatures in degrees Celsius and the equivalent temperatures in degrees Fahrenheit.

Mathematics

2 answers:

ElenaW [278]4 years ago

7 0

Answer:

Compare the equivalent temperatures as a ratio; if the ratios are equivalent, then the temperatures vary directly.

-v- ur welcome

san4es73 [151]4 years ago

6 0

Hi, thank you for posting your question here in Brainly.

Celsius and Fahrenheit are units of temperature, and they can be converted using a formula.

F = C*1.8 + 32

For example, 30°C is
F= 30*1.8 + 32
F = 86°F

Or an easier way to remember without memorizing the formula is by remembering the normal boiling point of water which is 100°C = 212°F.

You might be interested in

What is the measure of 7 shown in the diagram below?

Korolek [52]

Answer:

Step-by-step explanation:

5 0

3 years ago

What is the slope of the following equation? 5x - 2y = 13

Mila [183]

Answer:

$\frac{5}{2}$

Step-by-step explanation:

$5x - 2y = 13 \\ 5x - 13 = 2y \\ 2y = 5x - 13 \\ y = \frac{5}{2} x - \frac{13}{2} \\ equating \: it \: with \\ y = mx + b \\ slope(m) = \frac{5}{2}$

8 0

3 years ago

Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.

Step2247 [10]

Answer:

Remember, the expansion of $(x+y)^n$ is $(x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k$ , where $\binom{n}{k}=\frac{n!}{(n-k)!k!}$ .

Then,

$(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k$

Then, the coefficient of the term $p^{6-k}q^k$ is $\binom{6}{k}5^{6-k}2^k$

a) since 6-k=2, then k=4. So the coefficient of $p^2q^4$ is

$\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000$

b) since 6-k=5, then k=1. So, the coefficient of $p^5q$ is

$\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500$

c) since 6-k=3, then k=3. So, the coefficient of $p^3q^3$ is

$\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000$

6 0

3 years ago

9. Which correctly describes the root of the following cubic equation?

katrin2010 [14]

Option B is the answer and that because the photo below

3 0

3 years ago

at the science school, there is one microscope for every 5 students. The principal figures that in order to have one for every 4

Gennadij [26K]

Answer: 120 students

Explanation:

Let x be the number of scopes
Let a be the number of student at school

1x = 5 students
But 5x = a

1x = 4 students
But the principal needs 6 additional scope so that all the students can use it.

=> (x + 6) = 4 students
=> 4(x + 6) = a

Thus,
5x = 4(x + 6)
5x = 4x + 24
5x - 4x = 24
x = 24

So, there are 24 scopes.

Plug x in both equation and compare:

5x = a
5(24) = a
120 = a

4(x + 6) = a
4(24 + 6) = a
4(30) = a
120 = a

Therefore, the students at the school are 120

6 0

3 years ago