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Natasha2012 [34]
2 years ago
6

Can someone help me solve this problem?

Mathematics
1 answer:
jeka57 [31]2 years ago
8 0

Answer:

13

Step-by-step explanation:

cos17 = x/14

x = 14cos17

x= 13.38826658

to the nearest hundredth

x=13

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What equation is perpendicular to y=2x-3 and<br> passes through (-1, 2)?
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Answer:

\[y=-\frac{1}{2}x+\frac{5}{2}\]

Step-by-step explanation:

Equation of the given line: \[y=2x-3\]

Slope of the line = \[2\]

Slope of the perpendicular line = \[-\frac{1}{2}\]

So the equation of the perpendicular line:

\[y=-\frac{1}{2}x+c\]

This passes through the point (-1,2).Substituting in the equation:

\[2=-\frac{1}{2}*(-1)+c\]

=> \[c=2+\frac{1}{2}\]

=> \[c=\frac{5}{2}\]

So the equation of the line :

\[y=-\frac{1}{2}x+\frac{5}{2}\]

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To find the equation of this line in slope-intercept form (y = mx + b, where m is its slope and b is its y-intercept), we naturally need the slope and the y-intercept. We can see that the line intersects the y-axis at the point (0, 4) so our y-intercept is 4, and the line rises 4 along the y-axis for every 2 it runs along the x-axis, so its slope is 4/2 = 2. With this in mind, we can write the line's equation as

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