i) the least positive coterminal angle can be found by subtracting 2pi from your original angle. We subtract 2pi because 11pi/3 is larger than 2pi.
So: 11pi/3 - 2pi = 11pi/3 - 6pi/3 = 5pi/3 or
ii) The reference angle is the smallest angle you can make with the x-axis. Since 5pi/3 is in Quadrant IV, the reference angle is found by:
2pi - 5pi/3 = 6pi/3 - 5pi/3 = pi/3 or
iii) 5pi/3 or 300 degrees is found in Quadrant IV.
The approximate equation in slope intercept form is y = 3x + 2.
Solution:
Let us take (0, 2) and (1, 5) on the graph.
Equation of the line in slope-intercept form:
y = mx + b
where m is the slope of the line and b is the y-intercept of the line.
Slope of the line:
m = 3
y-intercept of the line is the value of y when x = 0.
Here the value of y is 2 when x = 0. That is (0, 2) is the point of y-intercept.
Therefore b = 2.
y = 3x + 2
Hence the approximate equation in slope intercept form is y = 3x + 2.