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2 years ago

Solve for a (log(a-1))^2 =log10

Mathematics

1 answer:

Elza [17]2 years ago

5 0

A function assigns the values. The value a is 11.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The given logarithmic function can be solved as shown below.

$(\log(a-1))^2 =\log10\\\\(\log(a-1))^2 =1\\\\(\log(a-1)) =\sqrt1\\\\\log(a-1) = 1\\\\10^1 = a-1\\\\a = 11$

Hence, the value a is 11.

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X= -8y + 8<br> x= -2y + 2 <br> How do I solve this system of equations

Agata [3.3K]

Answer:

According the the Property of Equality (POE), if a=b and b=c, then a=c.

If -8y + 8 = x and x = -2y + 2, substitute so that it becomes -8y + 8 = -2y + 2.

Solve from there:

Move the y variables to their own side.

-8y + 2y = 2-8

-6y = -6

y = -6

Then plug the y into either equation to find x.

x = -2y + 2

x = -2(-6) + 2

x = 12 + 2

x = 14

5 0

3 years ago

In 2003 the population of an African country was about 22.6 million people, which is 3 million more than 4 times the population

balandron [24]

Answer:

4p + 3= 22.6

There hope this helps you

3 0

3 years ago

The pressure, p, with which water passes through a pipe varies inversely as the square of the pipe's radius, 2. If k is the cons

iragen [17]

The variation equation is p = kr^2

<h3>How to determine the variation equation?</h3>

The variables are give as:

Pressure = P

Radius= r

The direct variation from p to the square of r is represented as:

$p\ \alpha\ r^2$

Express as an equation

p = kr^2

Where k represents the constant of variation

Hence, the variation equation is p = kr^2