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julia-pushkina [17]
2 years ago
6

In terms of net charge, how does an electrically polarized object differ from an electrically charged object?.

Physics
1 answer:
snow_tiger [21]2 years ago
5 0

Answer:

An electrically polarized object can carry no net charge

Example: charge Q at +x   and charge -Q at -x        for no net charge

An electrically charged object has a net charge on the object

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A force of 450N accelerated a box across a frictionless surface at a rate of 15 m/s^2. What is the mass of the box
larisa [96]
Formula:
F = ma

m = F÷A
m: mass F:force A: accelerarion

m = 450N ÷ 15m/s^2
= 30kg

Hope this helps :)
4 0
3 years ago
How is the voltage drop ΔV across the resistor related to the current I and the resistance R of the resistor? (Use any variable
MissTica

P = ΔV²/R

P = I²R

<u>Explanation:</u>

As a q passes by a resistor, it expends a (q V) where V is the potential drop between the resistor. This energy goes into radiation, much like the type a glob of putty that drops off a rock transforms its potential energy to heat when it strikes the bottom.

The transformation of potential energy into heat is referred to as dissipation. The power consumed in a resistor is the energy consumed per time. If an amount of Δq moves through the resistor in a time Δt, the power P = ΔqV/ Δt

                         P = ΔV²/R

                         P = I²R or IV

Where I is the current through the resistor, R and V is the voltage drop crossed it. The formula P = IV also provides the energy produced by a battery if I is the current spreading from the battery and V is its voltage.

7 0
4 years ago
A 7.91g bullet is fired into a 1.52-kg ballistic pendulum initially at rest and becomes embedded in it. The pendulum subsequentl
Stella [2.4K]

Answer:

D

Explanation:

By law of conservation of momentum:

momentum before collision = momentum after collision

m_{1} u_1 + m_2 u_2  = m_1 v_1 + m_2  v_2\\ m_1 = mass of bullet\\u_1 = initial speed of bullet\\m_2 = mass of pendulum\\u_2 = initial speed of pendulum\\v_1 = final speed of bullet\\v_2 = final speed of pendulum

Initial speed of bullet is unknown whereas initial speed of pendulum will be zero as it was at rest.

Final speed of bullet and pendulum will be equal as bullet is embedded in pendulum and both moves together a vertical distance of 6.89cm.

Using third equation of motion:

2 a S = v_{f}^2  - v_{i}^2

where:

a = -g = acceleration due to gravity = 9.8 m/s^2 ( for vertical motion)\\S = h = 6.89cm = Vertical height or distance it covers\\v_f = final speed = 0 (after covering 6.89cm)\\v_i = initial speed (unknown)

Thus by placing values v_i = 1.1620 m/s

this speed will be final speed of collision for the calculation of initial speed of bullet.

Putting values:

(7.91) * x + (1.52*10^3) * 0 = (7.91 + 1.52*10^3) * 1.162\\7.91 x = 1775.431\\x = 224m/s

This 224m/s = 0.224Km/s which is closest to D

8 0
3 years ago
11. When an object is speeding up in the positive direction, what vs happering to its
Alina [70]

Answer:

im pretty sure its b

Note that when the acceleration is negative — on the interval [0, 2) — that means that the velocity is decreasing. When the acceleration is positive — on the interval (2, 4] — the velocity is increasing. Speeding up and slowing down.

4 0
3 years ago
Made use of the whole time scale​
muminat

Answer:

What're you trying ask

Explanation:

7 0
3 years ago
Read 2 more answers
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