Question

A car sets off from the traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?

Answer 1

Answer:

1.6875m/s²

Explanation:

$acceleration = \frac{final \: velocity \: - \: initial \: velocity}{time \: taken}$

a = unknown.

v (final velocity) = 27m/s

u (initial velocity) = 0m/s (as the car was stationary in the traffic lights).

t (time taken) = 18s

$a = \frac{27 - 0}{16}$

acceleration = 1.6875m/s²

hope it helps. :)