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atroni [7]
3 years ago
10

A car sets off from the traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?

Physics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

1.6875m/s²

Explanation:

acceleration =  \frac{final \: velocity \:  -  \: initial \: velocity}{time \: taken}

<em> </em><em>a </em><em>=</em><em> </em><em>unknown.</em>

<em>v </em><em>(</em><em>final </em><em>velocity)</em><em> </em><em>=</em><em> </em><em>2</em><em>7</em><em>m</em><em>/</em><em>s</em>

<em>u </em><em>(</em><em>initial </em><em>velocity</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em><em>m</em><em>/</em><em>s </em><em>(</em><em>as </em><em>the </em><em>car</em><em> </em><em>was </em><em>stationary </em><em>in </em><em>the </em><em>traffic </em><em>lights)</em><em>.</em>

<em>t </em><em>(</em><em>time </em><em>taken)</em><em> </em><em>=</em><em> </em><em>1</em><em>8</em><em>s</em>

<em>a =  \frac{27 - 0}{16}</em>

<em>acceleration</em><em> </em><em>=</em><em> </em><em>1.6875</em><em>m</em><em>/</em><em>s²</em>

hope it helps. :)

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3 years ago
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An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0km/hour is blowing southward.
qaws [65]

Answer:

a)  correct answer is C , b) 14º  from the west to the north, c)   v_{1g} = 300.79 km / h

Explanation:

This is a relative speed exercise using the addition of speeds.

1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C

2 and 3) In this case we must compose the speed using the Pythagorean Theorem.

     v_{1a}² = v_{1g}² + v_{ag}²

where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth

in this case let's clear the speed of the airplane with respect to the Earth

  v_{1g} = √(v_{1a}² - v_{ag}²)

 v_{1g} = √ (310² - 75²)

 v_{1g} = 300.79 km / h

we find the direction of the airplane using trigonometry

   sin θ = v_{ag} / v_{1a}

   θ = sin⁻¹ (v_{ag} /v_{1a})

   θ = sin⁻¹ (75/310)

   θ= 14º

the pilot must direct the aircraft at an angle of 14º from the west to the north

7 0
3 years ago
A diver shines light up to the surface of a flat glass-bottomed boat at an angle of 30° relative to the normal. If the index of
son4ous [18]

Answer:

<h2>35</h2>

Explanation:

According to snell's law which states that the ratio of the sin of incidence (i) to the angle of refraction(n) is a constant for a given pair of media.

sini/sinr = n

n is the constant = refractive index

Since the diver shines light up to the surface of a flat glass-bottomed boat, the refractive index n = nw/ng

nw is the refractive index of water and ng is that of glass

sini/sinr = nw/ng

given i = 30°, nw = 1.33, ng = 1.5, r = angle the light leave the glass

On substitution;

sin 30/sinr = 1.33/1.5

1.5sin30 = 1.33sinr

sinr = 1.5sin30/1.33

sinr = 0.75/1.33

sinr = 0.5639

r = arcsin0.5639

r ≈35°

angle the light leave the glass is 35°

7 0
2 years ago
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ValentinkaMS [17]

Hi there!

We know that:

U (Potential energy) = mgh

We are given the potential energy, so we can rearrange to solve for h (height):

U/mg = h

g = 9.81 m/s²

m = 30 g ⇒ 0.03 kg

0.062/(0.03 · 9.81) = 0.211 m

8 0
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Substract two consecutive terms of the sequence to see if there is a common difference:

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As we can see, there is a common difference of -6.

Then, if a number of the sequence is given, the next one can be found by adding -6 (which is the same as subtracting 6).

Notice that the first term of the sequence is 3.

Then, the rule for the sequence is to start with 3 and add -6 repeatedly.

Therefore, the correct choice is option A) Start with 3 and add -6 repeatedly.

7 0
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