A car sets off from the traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?
1 answer:
Answer:
1.6875m/s²
Explanation:
<em> </em><em>a </em><em>=</em><em> </em><em>unknown.</em>
<em>v </em><em>(</em><em>final </em><em>velocity)</em><em> </em><em>=</em><em> </em><em>2</em><em>7</em><em>m</em><em>/</em><em>s</em>
<em>u </em><em>(</em><em>initial </em><em>velocity</em><em>)</em><em> </em><em>=</em><em> </em><em>0</em><em>m</em><em>/</em><em>s </em><em>(</em><em>as </em><em>the </em><em>car</em><em> </em><em>was </em><em>stationary </em><em>in </em><em>the </em><em>traffic </em><em>lights)</em><em>.</em>
<em>t </em><em>(</em><em>time </em><em>taken)</em><em> </em><em>=</em><em> </em><em>1</em><em>8</em><em>s</em>
<em></em>
<em>acceleration</em><em> </em><em>=</em><em> </em><em>1.6875</em><em>m</em><em>/</em><em>s²</em>
hope it helps. :)
You might be interested in
Explanation:
According to Newton's second law of motion, the rate of change of momentum is directly proportional to the applied unbalanced force. The mathematical expression is given by:
Where
F is the applied force
m is the mass of the object
v is the velocity with which it is moving
Momentum of a particle is given by the product of mass and velocity as :
Hence, this is the required solution.