All categories

3 years ago

A car sets off from the traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?

Physics

1 answer:

Katarina [22]3 years ago

6 0

Answer:

1.6875m/s²

Explanation:

$acceleration = \frac{final \: velocity \: - \: initial \: velocity}{time \: taken}$

a = unknown.

v (final velocity) = 27m/s

u (initial velocity) = 0m/s (as the car was stationary in the traffic lights).

t (time taken) = 18s

$a = \frac{27 - 0}{16}$

acceleration = 1.6875m/s²

hope it helps. :)

You might be interested in

Can someone help me w this ?

lukranit [14]

Answer:

i can't sorry

Explanation:

I didn't really pay attention in that class

7 0

2 years ago

A radio station broadcasts at a frequency of 600 kHz. Knowing that radio waves have a speed of 300 000 000 m/s, what is the wave

soldier1979 [14.2K]

Answer:

ccvtesgdujtdchgdrgggggggfrrrtyfaasdddfffghgdshh

6 0

3 years ago

You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide

rewona [7]

Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

(b). The electron will follow a circular path which travels along under constant magnetic field

$r = \frac{mV}{qB}$

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

4 0

2 years ago

Read 2 more answers

A 2kg block of which material would require 450 joules of thermal energy to increase its temperature by 1 degree Celsius?

12345 [234]

The block is made of A) Tin, as its specific heat capacity is $0.225 J/(g^{\circ}C)$

Explanation:

When an amount of energy Q is supplied to a sample of material of mass m, the temperature of the material increases by $\Delta T$ , according to the following equation :

$Q=mC_s \Delta T$

where $C_s$ is the specific heat capacity of the material.

In this problem, we have:

m = 2 kg = 2000 g is the mass of the unknown material

$Q = 450 J$ is the amount of energy supplied to the block

$\Delta T = 1^{\circ}C$ is the change in temperature of the material

Solving the equation for $C_s$ , we can find the specific heat capacity of the unknown sample:

$C_s = \frac{Q}{m \Delta T}=\frac{450}{(2000)(1)}=0.225 J/(g^{\circ}C)$

And by comparing with tabular values, we can find that this value is approximately the specific heat capacity of tin.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0

3 years ago

A disk 7.90 cm in radius rotates at a constant rate of 1 190 rev/min about its central axis. (a) Determine its angular speed. 12

Tanya [424]

Answer:

$124.62\ \text{rad/s}$

$3.71\ \text{m/s}$

$1.23\ \text{km/s}^2$

$20.28\ \text{m}$

Explanation:

r = Radius of disk = 7.9 cm

N = Number of revolution per minute = 1190 rev/minute

Angular speed is given by

$\omega=N\dfrac{2\pi}{60}\\\Rightarrow \omega=1190\times \dfrac{2\pi}{60}\\\Rightarrow \omega=124.62\ \text{rad/s}$

The angular speed is $124.62\ \text{rad/s}$

r = 2.98 cm

Tangential speed is given by

$v=r\omega\\\Rightarrow v=2.98\times 10^{-2}\times 124.62\\\Rightarrow v=3.71\ \text{m/s}$

Tangential speed at the required point is $3.71\ \text{m/s}$

Radial acceleration is given by

$a=\omega^2r\\\Rightarrow a=124.62^2\times 7.9\times 10^{-2}\\\Rightarrow a=1226.88\approx 1.23\ \text{km/s}^2$

The radial acceleration is $1.23\ \text{km/s}^2$ .

t = Time = 2.06 s

Distance traveled is given by

$d=vt\\\Rightarrow d=\omega rt\\\Rightarrow d=124.62\times 7.9\times 10^{-2}\times 2.06\\\Rightarrow d=20.28\ \text{m}$

The total distance a point on the rim moves in the required time is $20.28\ \text{m}$ .

8 0

3 years ago