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trapecia [35]
3 years ago
15

Which device used in the Hubble telescope was later adapted for commercial use?

Physics
1 answer:
netineya [11]3 years ago
4 0
The answer is CCD. The CCD, or the charge-coupled device was used in the Hubble Space telescope and was later adapted for commercial use.  CCD is a light-sensitive circuit used for storing and displaying data such as images.  This is also used in digital cameras today.

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What occurs between two atoms that do not easily lose electrons
CaHeK987 [17]
There is a covalent bond formed between two atoms that do not easily lose electrons. 

hope this helps :)
7 0
3 years ago
If an object with 1000 lb of weight is to be raised vertically from ground level to 5 ft in two seconds, how much power is requi
tino4ka555 [31]

Answer:

The power required = 3390.9 W

Explanation:

Power: This can be defined as the time rate of doing work. The S.I unit of power is Joules.

Mathematically it can be expressed as,

P = Work/time or

P =W×V...................... Equation 1

Where P = power, w = weight, V = velocity.

Also

V = d/t ..................... Equation 2

Where d = distance, t = time.

Conversion:   d = 5ft

If 1 foot =  0.3048 meters

Then, 5 ft = 5×0.3048 meters = 1.524 m.

W = 1000 lb

If 1 lb = 4.45 N,

Then 1000 lb = 1000× 4.45 N = 4450 N.

Given: d = 1.524 m, t = 2 s.

Substituting these values into equation 2

V = 1.524/2

V = 0.762 m/s.

Also substituting into equation 1

P = 4450×0.762

P = 3390.9 W.

Thus the power required = 3390.9 W

8 0
4 years ago
A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m
Lapatulllka [165]

Answer:

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

R = \frac{u^2Sin(2\theta)}{g}\\\\R = \frac{(30)^2sin(80^0)}{9.8}\\\\R = 90.46 \ m

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m

3 0
3 years ago
Which of these statements about light microscopes and electron microscopes is NOT true? A.) You can use light microscopes to obs
andrew-mc [135]
I think the correct answer from the choices listed above is option C. Preserving and staining samples for use with light microscopes is necessary;preserving and staining samples for use with electron microscopes is optional is not true about <span>light microscopes and electron microscopes</span>
6 0
3 years ago
Read 2 more answers
NEED HELP NOW!!! I WILL BRAINLIEST.
Sergio039 [100]

Answer:

1. Carbon-12

2. Nitrogen-13

3. Carbon-13

7 0
3 years ago
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