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a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
<span>The correct answer is option C. i.e.Equilateral triangles. All equilateral triangle have equal sides. Due to this these set of shapes will always be similar. Similarity in the sense that only the size of the triangles can change to large or smaller but the shape will be be similar always.</span>
Answer:
There are two significant figures in 2.200 x 10^7
Explanation:
Given data
Mass of skier m=65kg
Height of slope =80m
Potential energy possessed by the skier (positive work done) =12000J
Analysing his energy at half way point on the hill
Potential energy will be equal to kinetic energy
Applying the conservative principles of energy when the skier is at half way point in the hill
I.e
mgh= 1/2mv²
The masses will cancel out
gh=v²
Given g= 9.81m/s²
Let's solve for the velocity
v²=9.81*80
v=√784.8
v=28.0m/s
Now we can solve for the kinetic energy
KE= 1/2mv²
KE =1/2*60*28²
KE =47063.9/2
KE=23531.9J
Hence we can calculate the energy gained by the skier during his movement
Energy gained = KE-PE
= 23531.9-12000
= 11531.9J
A wave front has the form of a surface of a sphere
