3 years ago

When does the nuclear membrane disappear?

Physics

1 answer:

Ket [755]3 years ago

6 0

During the process of mitosis , specifically during prophase.

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WILL BE BRAINLIEST <br> HELP!!!

ivolga24 [154]

Answer:

(8.0÷6.0)×10[(-2)-(-3)]

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3 years ago

A projectile is fored vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile.

RSB [31]

Answer:

3683.67 m

Explanation:

Formula for maximum height of projectile is given by the equation;

h = u²/2g

Where u is initial velocity and g is acceleration due to gravity

We are given u = 190 m/s

Thus;

h = 190²/9.8

h = 36100/9.8

h = 3683.67 m

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3 years ago

Suppose that an object in free fall were somehow equipped with a speedometer. by how much would its speed readings increase with

alina1380 [7]

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4 years ago

Which element has 7 valence electrons ? A.nitogen(N) B.neon(Ne) C.lithium(Li) D.chlorine(CI)

aalyn [17]

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3 years ago

Read 2 more answers

A batter hits a ball at 35 degrees above the horizontal and it is caught 4 seconds later 100 meters from home plate. What is the

Mamont248 [21]

Answer:

$u=(26.5 i + 18.5j) m/s$

Explanation:

The range of a projectile is given by the formula

$d=\frac{u^2}{g} sin 2\theta$

where in this case, we have

d = 100 m is the range

u is the initial speed (the magnitude of the initial velocity)

g = 9.8 m/s^2 is the acceleration of gravity

$\theta = 35^{\circ}$ is the angle of projection

Solving for u, we find:

$u=\sqrt{\frac{dg}{sin 2\theta}}=\sqrt{\frac{(100)(9.8)}{sin(2\cdot 35^{\circ})}}=32.3 m/s$

Now we can easily find the components of the initial velocity:

$u_x = u cos \theta = (32.3)(cos 35^{\circ})=26.5 m/s\\u_y = u sin \theta = (32.3)(sin 35^{\circ})=18.5 m/s$

So, the initial velocity of the ball is

$u=(26.5 i + 18.5 j) m/s$

where i and j are the unit vector indicating the horizontal and vertical direction.

7 0

3 years ago