This solute-solvent interaction will release energy into the surroundings and makes the beaker warm.
<u>Explanation:</u>
The sulfuric acid is dissolved in water and it formed a solvation sphere of water molecules around the sulphur ions. So on stirring the beaker is getting warm. As the beaker is getting warm, this means the reaction occuring between sulfuric acid and water is exothermic reaction.
And so the energy is released into the surroundings. The energy released came from the breaking of bonds of sulfuric acid, as the acid is getting dissociated in water.
So, the release of energy in the surroundings lead to the warming of the beaker. Hence, the solute-solvent interaction release energy into the surroundings.
Answer:
197 + (35.5×3) = 303.5
Explanation:
relative formula mass is the sum of the relative atomic masses of the atoms in the formula ( AuCl3 )
Initial volume of the balloon = 
= 348 mL
Initial temperature of the balloon 
= 
Final volume of the balloon 
= 322 mL
Final temperature of the balloon = 
According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.
On plugging in the values,
Therefore, the temperature of the freezer is 276 K
Answer:
a. 2 HgO(s) ⇒ 2 Hg(l) + O₂(g)
b. 0.957 g
Explanation:
Step 1: Write the balanced equation
2 HgO(s) ⇒ 2 Hg(l) + O₂(g)
Step 2: Convert 130.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15
K = 130.0°C + 273.15
K = 403.2 K
Step 3: Calculate the moles of O₂
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 1 atm × 0.0730 L/0.0821 atm.L/mol.K × 403.2 K
n = 2.21 × 10⁻³ mol
Step 4: Calculate the moles of HgO that produced 2.21 × 10⁻³ moles of O₂
The molar ratio of HgO to O₂ is 2:1. The moles of HgO required are 2/1 × 2.21 × 10⁻³ mol = 4.42 × 10⁻³ mol.
Step 5: Calculate the mass corresponding to 4.42 × 10⁻³ moles of HgO
The molar mass of HgO is 216.59 g/mol.
4.42 × 10⁻³ mol × 216.59 g/mol = 0.957 g
Answer:
Option (3)
Explanation:
Wind energy is directly derived from the wind. In the places where wind blowing is quite frequent, there wind mills are being set up, and the turbines in it rotates due to the prevailing wind. Due to this continuous motion of turbines, it collects the wind energy and it is being transferred into electrical energy.
It is cost-effective and does not produce any kind of pollution and is completely a renewable energy, that it can generated again and again.
It does have certain drawbacks also, because <u>the area may sometime do not experience constant wind, due to which it cannot store energy. So frequent wind blowing areas are the best place to set up windmills</u>.
Thus, the correct answer is option (3)
