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2 years ago

The shape of the illuminated portion of the Moon as seen by an observer, usually on Earth:

Chemistry

1 answer:

Gekata [30.6K]2 years ago

4 0

Answer:moon phases

Explanation:

Moon phases because the moon phases changers every day

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Show that the Joule-Thompson Coefficient is zero for ideal gas.

melomori [17]

Answer:

Joule-Thomson coefficient for an ideal gas:

$\mu_{J.T} = 0$

Explanation:

Joule-Thomson coefficient can be defined as change of temperature with respect to pressure at constant enthalpy.

Thus,

$\mu_{J.T} = \left [\frac{\partial T}{\partial P} \right ]_H$

Also,

$H= H (T,P)$

$Differentiating\ it,$

$dH= \left [\frac{\partial H}{\partial T}\right ]_P dT + \left [\frac{\partial H}{\partial P}\right ]_T dT$

Also, $C_p$ is defined as:

$C_p = \left [\frac{\partial H}{\partial T}\right ]_P$

$So,$

$dH= C_p dT + \left [\frac{\partial H}{\partial P}\right ]_T dT$

Acoording to defination, the ethalpy is constant which means $dH = 0$

$So,$

$\left [\frac{\partial H}{\partial P}\right ]_T = -C_p\times \left [\frac{\partial T}{\partial P}\right ]_H$

$Also,$

$\mu_{J.T} = \left [\frac{\partial T}{\partial P}\right ]_H$

$So,$

$\left [\frac{\partial H}{\partial P}\right ]_T =-\mu_{J.T}\times C_p$

For an ideal gas,

$\left [\frac{\partial H}{\partial P}\right ]_T = 0$

So,

$0 =-\mu_{J.T}\times C_p$

Thus, $C_p$ ≠0. So,

$\mu_{J.T} = 0$

6 0

2 years ago

100 points will to help

FromTheMoon [43]

Answer:

6. 350kg

7. 800kg

8.600 meters

Explanation: I don’t like Stealing point but this is what I think I should give you and I don’t know how your teacher learn you this...

8 0

2 years ago

Read 2 more answers

PREDICT Do you think warming a cannonball in a fire has any effect

Zanzabum

I think yes because the heat from the fire will transferred to the cannon ball and it will cause something with its energy to change effect.

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2 years ago

Which of the following correctly represents the radioactive decay of cesium-137?<br><br>

pishuonlain [190]

What are the answers ??

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2 years ago

A solution of ammonium carbonate is mixed with a solution of magnesium nitrate. If magnesium carbonate is insoluble in water, wh

Dahasolnce [82]

Tbh I don’t know I tried to answer it

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2 years ago