Answer:
30.7 g of O₂ are produced
Explanation:
This is a redox reaction, where the peroxide is reduced to oxygen and oxidized to hydroxide. The equation is this one:
2Na₂O₂ + 2H₂O → 4NaOH + 3O₂
We assume that water is in excess, so the peroxide is the limiting reagent.
We convert the mass to moles: 50 g . 1mol / 78 g = 0.641 moles
2 moles of peroxide can produce 3 moles of oxygen (according to stoichiometry)
Then, 0.641 moles of peroxide will produce (0.641 . 3 ) /2 = 0.961 moles O₂
Finally, we convert the moles to mass: 0.961mol . 32 g / 1mol = 30.7 g of O₂
