All categories

1 year ago

Using a rounded version of a conversion ratio allows for a quick estimate of a unit conversion

Mathematics

1 answer:

dolphi86 [110]1 year ago

6 0

The conversion ratio that can be illustrated will be converting 2030m to kilometers.

<h3>How to illustrate the conversion?</h3>

The unit conversion that can be illustrated based on the information can be convert 2030m to kilometers.

It should be noted that 1000 meters makes 1 kilometer. Therefore, rounding up 2030m mentally will be 2000m and the conversion to kilometers will be:

= 2000/1000

= 2 km

Learn more about ratio on:

brainly.com/question/2328454

#SPJ1

You might be interested in

Paul needs 40 pounds of 48% silver alloy to finish a collection of jewelry. How many pounds each of 45% silver alloy and 60% sil

Salsk061 [2.6K]

Equation:
silver + silver = silver
0.45x + 0.60(40-x) = 0.48*40
----------------
45x + 60*40 - 60x = 48*40

--------
-15x = -12*40
x = (4/5)40
x = 32 lbs (amt of 45% slloy needed)
40-x = 8 lbs (amt of 60% alloy needed)

8 0

2 years ago

Please help on question b

Viktor [21]

Answer:

Step-by-step explanation:

Number of males who exclusively drink coffee: 21.

Total number of people: 100

P(MdC) = 21/100 * 100% = 21%

8 0

3 years ago

Solve for a, v0, and t

Burka [1]

Answer:

Step-by-step explanation:

∡x = v0t + 1/2 at²

∡x / v0t = 1/2 at²

2∡x / v0t =at²

a = 2∡x / v0t³

that's your answer:)

5 0

3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago

Directions: Select all the correct answers.

Kay [80]

The correct answer is C and D .

4 0

3 years ago