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IgorLugansk [536]
2 years ago
12

An isosceles triangle has side lengths of 15.6 units and 20.33 units. What is the greatest possible value of the perimeter of th

e triangle?
Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
6 0

Answer:

56.26

Step-by-step explanation:

An isosceles triangle has two sides that are the same length, and one side that is the same length. We have two sizes, so two find the greatest possible perimeter we must assume that the greater size is the value for the two sides, and the smaller size the value for the single side. In other words:

x = 15.6 + 2(20.33)

x = 56.26

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A model with 12 squares labeled exact value and 3 squares labeled error. A model with 18 squares labeled exact value and 3 squar
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Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

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Step-by-step explanation:

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1/sinx = 4

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sinθ = opposite/hypotenuse

from sinx = 1/4

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adj² = 4²-1²

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adj = √15

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tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

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sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

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tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
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