Answer:
523.333 cubic yards
Step-by-step explanation:
The formula for the volume of a sphere is
where
is the radius.
The radius of the given sphere is
yards and
.
Therefore, we can substitute in the radius and solve:
cubic yards
(f+g-k)(x) means to add the equations f(x) and g(x) then subtract k(x)
2x^2 + 3x + 4x - 9 = 2x^2 +7x -9
2x^2 + 7x - 9 - x^2 -7x = x^2 -9
The answer is : x^2 - 9
Radius = 100m
Circumference of a circle = 2πr
= 2 × π× 100
=628.31m
<span> add</span><span> up the two equivalent fractions </span>
<span>Add the two equivalent fractions</span><span> which now have a common denominator</span>
<span>Combine the numerators together, put the sum or difference</span><span> over the common denominator then reduce to lowest terms if possible. tell me if this helped you.</span>
Answer:
![\text{Volume of cat box}=3.52\text{ ft}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cat%20box%7D%3D3.52%5Ctext%7B%20ft%7D%5E3)
Step-by-step explanation:
We have been given that Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a height of 2 feet. We are asked to find the volume of the box.
Let us convert one and one tenth feet into decimal.
![1\frac{1}{10}=\frac{11}{10}=1.1](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B10%7D%3D%5Cfrac%7B11%7D%7B10%7D%3D1.1)
Since the cat box is in form of cuboid, so its volume will be equal to the product of length, width and height as:
![\text{Volume of cat box}=1.10\text{ ft}\times 1.6\text{ ft}\times 2\text{ ft}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cat%20box%7D%3D1.10%5Ctext%7B%20ft%7D%5Ctimes%201.6%5Ctext%7B%20ft%7D%5Ctimes%202%5Ctext%7B%20ft%7D)
![\text{Volume of cat box}=3.52\text{ ft}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cat%20box%7D%3D3.52%5Ctext%7B%20ft%7D%5E3)
Therefore, the volume of the cat box is 3.53 cubic feet.