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GarryVolchara [31]
3 years ago
14

In a right triangle, Sin (30 + x) º = Cos (3x) º. What is the value of x?

Mathematics
1 answer:
pogonyaev3 years ago
5 0

Answer:

x=15^\circ

Step-by-step explanation:

In a right triangle:

\sin \theta =cos(90^\circ-\theta) $ (Complementary angles)

Therefore, given:

Sin (30 + x) \º = Cos (3x) \º\\30+x+3x=90^\circ\\30+4x=90^\circ\\4x=90^\circ-30^\circ\\4x=60^\circ\\$Divide both sides by 4\\x=15^\circ

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