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Vika [28.1K]
1 year ago
13

What fraction of this shape is shaded?

Mathematics
1 answer:
Lilit [14]1 year ago
5 0
15% it’s running
That’s all I’m aware of
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Help Q-Q 7/10c =4 1/5
shepuryov [24]

\huge\mathfrak\green{answer}

= q -   \frac{q7}{10} c =  \frac{41}{5}

\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

=  -  \frac{cq7}{10}  =  \frac{41}{5}  - q

\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

=  - cq7 = 82 - 10q

\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

\huge\mathfrak\green{thank \: you}

5 0
3 years ago
Read 2 more answers
∠a and ∠b are complementary angles. ∠a measures 32੦. What is the measure of ∠b?
Ganezh [65]

Answer:

b = 58

Step-by-step explanation:

Complementary angles add to 90 degrees.

a+b = 90

32+b = 90

Subtract 32 from each side

32+b-32 = 90-32

b = 58

3 0
3 years ago
Read 2 more answers
Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a
liberstina [14]
First plane: 496x
<span>Second plane:  558( x - 1/2) </span>

<span>Equation: 496x = 558( x - 1/2) </span>

<span>Solving  x = 9/2 ,  or  x = 4.5 hours.

Hope this helps.</span>
7 0
3 years ago
getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0
3 years ago
I need to find the value of x for this diagram
Burka [1]
X is 50.  The lengths of the radii extending out from the center to the chords are the same length, therefore, the chords are the same distance from the center and have the same measure.
8 0
2 years ago
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