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Burka [1]
3 years ago
5

Hon rolled a bowling ball so that it traveled 60 feet in 3 seconds.

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

1200

Step-by-step explanation:

the ball is going at 20 fps, 20x60 is 1200

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11. Use the fact that 19 X 33 = 627 to solve the problems and justify<br><br> your reasoning
topjm [15]
<h2>19 X 33 = 627,  justified.</h2>

Step-by-step explanation:

We have,

19 × 33 = 627

Use the fact and justify.

L.H.S. = 19 × 33

= (20 - 1) (20 + 13)

Using the identity,

(x - a)(x + b) = x^{2} - (a - b)x - ab

Here, x = 20, a = 1 and b = 13

= 20^{2} - (1 - 13)20 - 1(13)

= 400 - (- 12)20 - 13

= 400 + 240 - 13

= 640 - 13

= 627

= R.H.S., justified.

Thus,  19 X 33 = 627,  justified.

8 0
3 years ago
8. Calculate Cell A normally divides once every two days. If its control mechanisms aren't working correctly, cell A divides six
frozen [14]
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5 0
2 years ago
HELPP ASAP!!!!! Rectangle RSTU and the image R’S’T’U’ are graphed on the coordinate grid below.
mylen [45]
270° clockwise rotation & 90° counterclockwise rotation
6 0
3 years ago
Read 2 more answers
Find the value of x
gayaneshka [121]

Answer:

42°

Step-by-step explanation:

Since all the angles in the figure add up to 180°...

180 - 54 = 126

3x = 126°

x = 126 ÷ 3 = 42

4 0
3 years ago
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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