A cube has volume 1200 cubic inches. Write the edge length of the cube as a power.
1 answer:
You might be interested in
I'm partial to solving with generating functions. Let
Multiply both sides of the recurrence by and sum over all
.
Shift the indices and factor out powers of as needed so that each series starts at the same index and power of
.
Now we can write each series in terms of the generating function . Pull out the first few terms so that each series starts at the same index
.
Solve for :
Splitting into partial fractions gives
which we can write as geometric series,
which tells us
# # #
Just to illustrate another method you could consider, you can write the second recurrence in matrix form as
By substitution, you can show that
or
Then solving the recurrence is a matter of diagonalizing the coefficient matrix, raising to the power of , then multiplying by the column vector containing the initial values. The solution itself would be the entry in the first row of the resulting matrix.
Answer:
The area of the triangle is 48 unit²
Step-by-step explanation:
The given vertices of the triangle are;
(-2, 5), (-4, -3), and (3, 1)
The formula for finding the area of a triangle with given coordinates of the vertices is as follows;
Substituting gives;
The area of the triangle = 48 unit².