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1 year ago

Please help! I don't know how to do slopes.

Mathematics

1 answer:

fomenos1 year ago

3 0

The slope of the given line in the image is -4 , Option A is the answer.

<h3>What is the equation of a straight line ?</h3>

The equation of the straight line is given by

y =mx +c ,

Where m is the slope , C is the intercept

The line is passing through the point

(-1,8) ,(2,-4)

The slope is given by

m = (y₂-y₁) /(x₂-x₁)

m = (-4 - 8 )/(2 +1)

m = -12/3

m = -4

Therefore the slope of the given line in the image is -4 , Option A is the answer.

To know more about Straight Line equation

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Refer to Table 4-4. If these are the only four sellers in the market, then the market quantity supplied at a price of $4 is

NeTakaya

All things being equal; demand decreases, as price increases.

The quantity supplied when price is $4 is 28

From table 4.4 (see attachment).

When price = $4, we have the following supplies:

Firm A = 6
Firm B = 6
Firm C = 8
Firm D = 10

So, the total supply at $4 is:

$Total = 4 + 6 + 8 + 10$

$Total = 28$

Hence, the quantity supplied when price is $4 is 28

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5 0

2 years ago

Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r

Wewaii [24]

Table of the graph:
x: 1 2 3
y: 5 25 125

Average Rate of Change = $\frac{y_{2}-y_{1} }{x_{2} - x_{1} }$

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100

So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.

8 0

3 years ago

Suppose that angles A and B are complementary angles, where A is 5 times

Alla [95]

Answer:

105

Step-by-step explanation:

Let the angle of B be x

According to the question,

5x+x=90

or, 6x=90

or, x=15

The angle of B is 15

The angle of A is (15*5)=75

The supplementary angle of A is

(180-75)=105

4 0

2 years ago

Given log630 ≈ 1.898 and log62 ≈ 0.387, log615 =

Tom [10]

$\log_630\approx1.898\\\\\log_62\approx0.387\\\\\log_615=\log_6\dfrac{30}{2}=\log_630-\log_62\approx1.898-0.387=1.511\\\\Used:\\\\\log_ab-\log_ac=\log_a\dfrac{b}{c}$