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pishuonlain [190]
2 years ago
7

Please help! I don't know how to do slopes.

Mathematics
1 answer:
fomenos2 years ago
3 0

The slope of the given line in  the image is -4 , Option A is the answer.

<h3>What is the equation of a straight line ?</h3>

The equation of the straight line is given by

y =mx +c ,

Where m is the slope , C is the intercept

The line is passing through the point

(-1,8)  ,(2,-4)

The slope is given by

m = (y₂-y₁) /(x₂-x₁)

m  = (-4 - 8 )/(2 +1)

m = -12/3

m = -4

Therefore the slope of the given line in  the image is -4 , Option A is the answer.

To know more about Straight Line equation

brainly.com/question/959487

#SPJ1

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Use the explicit formula an = a + (n-1). d to find the 500th term of the
nadezda [96]

Answer:

Step-by-step explanation:

The difference is a2 - a1 = 31 - 24 = 7

n = 500

a500 = a1 + (500 - 1) * 7

a500 = 24 + 499 * 7

a500 = 24 + 3493

a500 = 3517

8 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Help me with this please
alina1380 [7]
If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40 
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y 
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x. 
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair. 
6 0
4 years ago
Challenge 5 Rani, Layla and Tash take part in a basketball competition. Rani scores 4 times as many baskets as Layla. Tash score
Murljashka [212]

Answer:

Step-by-step explanation:

r=4*l

t=r-8

t=4l-8

r+t+l=100

4l+4l-8+l=100

9l-8=100

+8 +8

9l=108

:9. :9

l=12 Layla score

4*12=48 Rani score

48-8=40 Tash score

verify 12+40+48=100 correct

4 0
4 years ago
This table represents the relationship between m, the amount of money an employee has in the morning, and f, the amount of money
uranmaximum [27]

Answer:

f= m - 5.5

Step-by-step explanation:

According to the table m is 15.25, so you would subtract 5.5 and you get 9.75 = f

7 0
2 years ago
Read 2 more answers
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