Answer:
Step-by-step explanation:
Price of one ticket = $4
Price of t tickets = 4t
1) 4t + 72 > 400
t > (400-72)/4
2) 4t + 72 > 400
4t + 72 - 72 > 400 - 72 {subtract 72 from both sides}
4t > 328
4t/4 > 328/4 {divide both sides by 4}
t > 82
The answer to your problem is A 1/3, is the possibility for a passenger who arrives at noon.
Answer:
is there any pic to refer the question?
Step-by-step explanation:
The distance is 2.23606 (2.24 rounded)
