<span>This question relates to a common concept in Chemistry called "pressure volume work" which measures work done by gases when they compress or expand due to pressure. In equation form work = pressure x change in volume. In this situation work is expressed in L x ATM (atmosphere).
First we calculate the change in volume by subtracting final volume by initial volume. In this case the volume doubled so it is 2v-v which equals v (or 240l).
Next we convert bar to ATM. 1 bar is 100 kilopascale and 101.325 kilo pascals is 1 atmosphere, so in general 1 bar is usually considered to be 1 ATM. If we want to be very precise we would divide 100kilopasczle by 101kilopascalw per bar to get .987 ATM.
In this example we will use 1
So work = 1 ATM x 240l = 240 ATM x l</span>
Answer:
response I believe
Explanation:
i'm pretty sure it's a response cause it's the animal responding to needing water and being thirsty
hope this helps! :)
Answer:
i think its the first one
Explanation:
i could be wrong
The molar mass of unknown gas is 63.5 g/mol
calculation
let the unknown gas be represent by letter Y
The rate of effusion of a gas varies inversely with square root of molar mass
that is R(CH4)/ R(Y)= √[(M(Y)/M(CH4)]
= 47.8 ml/min/24.0ml/min= √[(Y/16g/mol)]
square both side to remove square root sign
=47.8²ml/min /24²ml/min= Y/16 g/mol
=2284.84ml/min/576ml/min=Y/16g/mol
multiply both side by 16
y =63.5 g/mol
Explanation:
Rotting, withering, heat and light emission, precipitate formation, gas evolution, or a change of appearance.