Metals are to the left of the zig-zag, nonmetals are to the right, and metalloids lie on/beside the line.
Question requires a change resulting in an increase in both forward and reverse reactions. Now lets discuss options one by one and see there impact on rate of reactions.
1) <span>A decrease in the concentration of the reactants:
When concentration of reactant is decreased it will shift the equilibrium in Backward direction, so resulting in increasing the backward reaction and decreasing the forward direction. Hence, this option is incorrect.
2) </span><span>A decrease in the surface area of the products:
Greater the surface Area greater is the chances of collision and greater will be the rate of reaction. As the surface area of products is decreased it will not favor the backward reaction. Hence again this statement is incorrect according to given statement.
3) </span><span>An increase in the temperature of the system:
An increase in temperature will shift the reaction in endothermic side. Hence, if the reaction is endothermic, an increase in temperature will increase the rate of forward direction or if the reaction is exothermic it will increase the rate of reverse direction. Hence, this option is correct according to given statement.
4) </span><span>An increase in the activation energy of the forward reaction:
An increase in Activation energy will decrease the rate of reaction, either it is forward or reverse. So this is incorrect.
Result:
Hence, the correct answer is,"</span>An increase in the temperature of the system".
The volume of H₂ evolved at NTP=0.336 L
<h3>Further explanation</h3>
Reaction
Decomposition of NH₃
2NH₃ ⇒ N₂ + 3H₂
conservation mass : mass reactants=mass product
0.28 NH₃= 0.25 N₂ + 0.03 H₂
2 g H₂ = 22.4 L
so for 0.03 g :
I think it is trace evidence since it is really small and hard to find.
Answer:
the concentration of new solution = 0.025 M
Explanation:
Given that :
The initial volume V_1 = 15 mL
Initial concentration M_1 = 0.16 M
Final volume V_2 = 95 mL
Final concentration M_2 = ???
We know that M_1 × V_1 = M_2V_2
Making M_2 the subject of the formulae; we have :
M_2 = (M_1 × V_1)/V_2
M_2 = (0.16 × 15)/ 95
M_2 = 0.025 M
Thus, the concentration of new solution = 0.025 M
