Answer:
72.03 %
Explanation:
Total mass of dolomite = 9.66 g
Let the mass of Magnesium carbonate = x g
The mass of calcium carbonate = 9.66 - x g
Calculation of the moles of Magnesium carbonate as:-
Molar mass of Magnesium carbonate = 122.44 g/mol
The formula for the calculation of moles is shown below:
Thus,
Calculation of the moles of calcium carbonate as:-
Molar mass of calcium carbonate = 100.0869 g/mol
Thus,
According to the reaction shown below:-
![MgCO_3\rightarrow MgO+CO_2](https://tex.z-dn.net/?f=MgCO_3%5Crightarrow%20MgO%2BCO_2)
![CaCO_3\rightarrow CaO+CO_2](https://tex.z-dn.net/?f=CaCO_3%5Crightarrow%20CaO%2BCO_2)
In both the cases, the oxides formed from the carbonates in the 1:1 ratio.
So, Moles of MgO =
Molar mass of MgO = 40.3044 g/mol
Thus, Mass = Moles*Molar mass =
Moles of CaO =
Molar mass of CaO = 56.0774 g/mol
Thus, Mass = Moles*Molar mass =
Given that total mass of the oxide = 4.84 g
Thus,
![\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84](https://tex.z-dn.net/?f=%5Cfrac%7B40.3044x%7D%7B84.3139%7D%2B56.0774%5Ctimes%20%5Cfrac%7B-x%2B9.66%7D%7B100.0869%7D%3D4.84)
![-694.1618435x+45673.48749\dots =40843.38968\dots](https://tex.z-dn.net/?f=-694.1618435x%2B45673.48749%5Cdots%20%3D40843.38968%5Cdots)
![x=\frac{4830.09780\dots }{694.1618435}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4830.09780%5Cdots%20%7D%7B694.1618435%7D)
![x=6.9582](https://tex.z-dn.net/?f=x%3D6.9582)
Thus, the mass of Magnesium carbonate = 6.9582 g