Which part of a cell directs the cell's activities and holds its DNA?

Chemistry

2 answers:

neonofarm [45]3 years ago

4 0

Answer:

Nucleus is the answer

A micrograph of animal cells, showing the nucleus (stained dark red) of each cell. Known as the cell's “command center,” the nucleus is a large organelle that stores the cell's DNA (deoxyribonucleic

rewona [7]3 years ago

3 0

Answer:

nucleus is the part of a cell directs the cells Activities and holds it's DNA

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Which of the following lists elements in order of increasing malleability?

hodyreva [135]

Malleability is the property due to which substances tend to hammered into thin sheets when pressure is applied. Malleability is observed in metal as the metal atoms are bound by metallic bonds. The layers of metal atoms can roll over each other without breaking the metal bond when pressure is applied. In the periodic table malleability decreases as the metallic nature decreases. Among the given metals Al is the most metallic element, followed by Zinc an Carbon is a non metal. Therefore, the order of increasing malleability will be C, Zn, Al

8 0

3 years ago

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explain observation made when anhydrous calcium chloride and anhydrous copper (ii) sulphate are separately exposed to the atmosp

Burka [1]

Answer:

Anhydrous calcium chloride dissolves and becomes liquid

Anhydrous copper (ii) sulphate will produce crystal particles

Explanation:

Anhydrous calcium chloride is deliquescent and hence when it is exposed to air, it absorbs water from air. After absorbing water, it dissolves and after some time a pool of clear liquid appears.

Anhydrous copper (ii) sulphate will form crystal structures and the following reaction will takes place

CuSO4 + 5 H20 --> CuSO4.5H2O

6 0

3 years ago

A student plans to use a density versus solution concentration standard curve to identify the sodium chloride concentration in a

Art [367]

Answer:

a. 0.50 g, 1.0 g, 1.5 g, 2.0 g, 2.5 g;

g. 0.1 g, 0.5 g, 1.0 g, 1.5 g, 2.0 g

Explanation:

The percent mass is defined as a ratio between the mass of a solute and mass of a solution:

$\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%$