We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
A local sorority sold hot dogs and bratwursts at the spring fling picnics. The first day they sold 8 dozen hotdogs and 13 dozen
1 answer:
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Answer:
2
Step-by-step explanation:
let the other leg be x
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 1² = 3²
x² + 1 = 9 ( subtract 1 from both sides )
x² = 8 ( take the square root of both sides )
x =
=
= ×
= 2
← exact value
