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3 years ago

0.018 as a fraction in simplest form

2 answers:

7 0

⇒We turn to a rational expression.

0.018 = $\frac{18}{1000}$

⇒We simplifty

$\frac{18/2}{1000/2}$

= $\frac{9}{500}$

Have a nice days.............

ki77a [65]3 years ago

5 0

$0.018=\dfrac{18}{1000}=\dfrac{9}{500}$

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valentina_108 [34]

Answer:

a. when x=1 so substitute 1 to any X in the given equation.

y=-3(1)+2.5

y=-3+2.5

y=-0.5

b.when x is -1.5 so substitute -1.5 to any x in the equation

y=-3(-1.5)+2.5

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3 years ago

Emy paid 24.50 for 4 baskets of apples. How much did she pay for each basket?

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Answer:

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Step-by-step explanation:

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3 years ago

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sasho [114]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.

kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = $\frac{38}{60} = 0.634$

Therefore, the probability is given by:

$P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]$

P $(p\leq 0.634) = P[z\leq -1.87188]$

P $(p\leq 0.634) = P[z\leq -1.87] = 0.0298$

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

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3 years ago