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Reptile [31]
3 years ago
11

How many molecules of ascorbic acid(vitaminC, C6H8 O6 )are in a 500 mg tablet?

Chemistry
2 answers:
Olegator [25]3 years ago
7 0

Answer:

1.71 × 10²¹ molecules

Explanation:

1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:

500 mg × (1 g / 1000 mg) = 0.500 g

The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:

0.500 g × (1 mol/ 176.12 g) = 0.00284 mol

In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:

0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule

dem82 [27]3 years ago
5 0

Answer:

Explanation:

1) molar mass of the C6H8O6, you need to consult the atomic weight of the C, H and O atoms that are in the periodic table: C is 12; H is 1; O is 16 (12x6)+(1x8)+(16x6)= 176g/mol  176 g = 1 mol 0,5 g =  x mol                500mg= 0,5 grams  molar mass = mass÷ moles 176 = 0,5÷ x x= 2,84 x 10⁻³ mol  2) To find the number of molecules present in those 2,84 x 10⁻³ mol we need to multiple the moles by the Avogadro's constant No. of molecules = Avogadro's constant  x n° of moles No. of molecules = 6.022 x 10²³ x 2,84 x 10⁻³ = 1.71 x 10²¹ molecules of vit C.

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19 which term represents an intermolecular force in a sample of water
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3 years ago
A gas occupies a volume of 60 L at a temperature of 0.5 K. What will the volume be at 4 K?
Flauer [41]

Answer:

480 L

Explanation:

In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.

As we can see, Charles's Law is:

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

or, initial volume over initial temperature equals final volume over final temperature.

In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for V_{2}:

--------------------------------------------------------------------------------------------------------------

(60) / (0.5) = V_{2} / (4)

↓

120 = V_{2} / 4

×4           ×4

↓

V_{2} = 480 L

--------------------------------------------------------------------------------------------------------------

There's our answer! Feel free to comment if you have any questions about my answer :)

3 0
3 years ago
In this stoichiometry problem, determine the limiting reactant.
Tanya [424]

Answer:

Limiting reactant is NiSO₄

Explanation:

The reaction of aluminum metal with aqueous nickel(II)  sulfate to produce aqueous aluminum sulfate and nickel is:

2 Al(s) + 3 NiSO₄ → Al₂(SO₄)₃ + 3 Ni  

<em>That means 2 moles of Al react with 3 moles of nickel sulfate.</em>

<em />

Moles of Al and NiSO₄ are:

Al: 108g × (1mol / 26.98g) = 4.00 moles of Al

NiSO₄: 464g × (1mol / 154.75g) = 3.00 moles of NiSO₄

For a complete reaction of aluminium there are necessary:

4.00mol Al ₓ ( 3 moles NiSO₄ / 2 moles Al) = 6 moles of NiSO₄

As you have just 3.00 moles of NiSO₄, the <em>limiting reactant is NiSO₄</em>

8 0
3 years ago
Compare and contrast the differences between plant animal cells
Step2247 [10]

Answer:

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Explanation:

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