Number of oxygen atoms present in 7.15×10²³ molecules of mannose are 1.92≈2 a m u .
<h3>What is mannose sugar?</h3>
D-mannose is a simple sugar found in many fruits. It is related to glucose. In some cells it occurs naturally in the body.
Mannose is a six-carbon sugar found in a variety of fruits and vegetables. This sugar is not found free in foods. It is a part of polysaccharide chains attached to a variety of proteins.
To calculate number of oxygen atoms present in 7.15×10²³ molecules of mannose-
Since,
1 molecule of oxygen=2.303×10²³ no. of atoms
Here, total number of molecules of oxygen is 6.
Therefore, 6 molecule of oxygen =6×2.303×10²³÷7.15×10²³
=1.92≈2 a m u .
Hence, the total number of oxygen atoms in 7.15×10²³ molecules of mannose is 1.92 ≈2 a m u.
Learn more about mannose sugar, here:
brainly.com/question/7008130
#SPJ4
Answer:
Only gives spontaneous reaction.
Explanation:
A redox reaction will be spontaneous if standard reduction potential () of the reaction is positive. Because it leads to negative standard gibbs free energy change (), which is a thermodynamic condition for spontaneity of a reaction.
Where and represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.
(1) Oxidation: ;
Reduction: ;
So,
Hence this pair will give spontaneous reaction.
(2) Similarly as above,
Hence this pair will give non-spontaneous reaction.
(3) Similarly as above,
Hence this pair will give non-spontaneous reaction.
(4) Similarly as above,
Hence this pair will give non-spontaneous reaction.
55.0 miles per hour converted into meters is 1475.232 meters per minute
It's the second one. cause u have to add