How many $4$-digit positive integers exist that satisfy the following conditions: (A) Each of the first two digits must be $1$,

Question

1 year ago

14

$4$, or $5$, and (B) the last two digits cannot be the same digit, and (C) each of the last two digits must be $5$, $7$, or $8$

1 answer:

Vilka [71] · Answer 1 · 2023-09-19T08:22:35+03:00

4 0

Answer:

54 possibles

Step-by-step explanation:

Digit ONE 3 choices

Digit two 3 choices

digit three 3 choices

digit four 2 choices

3 x 3 x 3 x 2 = 54 choices meet all of the conditions