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vichka [17]
2 years ago
14

How many $4$-digit positive integers exist that satisfy the following conditions: (A) Each of the first two digits must be $1$,

$4$, or $5$, and (B) the last two digits cannot be the same digit, and (C) each of the last two digits must be $5$, $7$, or $8$
Mathematics
1 answer:
Vilka [71]2 years ago
4 0

Answer:

54 possibles

Step-by-step explanation:

Digit ONE    3 choices

Digit two      3 choices

digit three    3 choices

digit  four      2 choices    

        3  x  3   x  3  x  2   = 54 choices meet all of the conditions

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Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation
Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

                         f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

                           A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.

Download docx
3 0
3 years ago
(PLEASE HELP I WILL GIVE BRAINLIEST IF CORRECT (40 POINTS)
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Answer:

2800 - 4000

Step-by-step explanation:

40 × 70 = 2800

50 × 80 = 4000

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Answer:

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Step-by-step explanation:

Area = W × L

W = A / L = \frac{50x^5y^5}{25x^3y} = 2x²y⁴

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