Question

PLEASE HELP ME SOLVE FOR X

Answer 1

Looks like the labeled angle is bisected, in which case we can apply the angle bisector theorem. For this triangle, it says

$\dfrac x3=\dfrac{x+2}{x+4}$

Solve for $x$:

$x(x+4)=3(x+2)$

$x^2+4x=3x+6$

$x^2+x-6=0$

$(x+3)(x-2)=0$

Then either $x=-3$ or $x=2$, but since $x$ is a length, it must be positive. So x = 2.