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3 years ago

PLEASE HELP ME SOLVE FOR X

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

Looks like the labeled angle is bisected, in which case we can apply the angle bisector theorem. For this triangle, it says

$\dfrac x3=\dfrac{x+2}{x+4}$

Solve for $x$ :

$x(x+4)=3(x+2)$

$x^2+4x=3x+6$

$x^2+x-6=0$

$(x+3)(x-2)=0$

Then either $x=-3$ or $x=2$ , but since $x$ is a length, it must be positive. So <em>x</em> = 2.

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Help me please!!!!!!

Leokris [45]

Answer:

Both figures have a perimeter of 112 inches.

Step-by-step explanation:

Question 5:

You are given a 6-sided shape, but only 4 sides. To find the perimeter, you need to account for the lengths of the other two sides. As all the angles are right angles, the length of the top horizontal side is equal to the combined length of the bottom two horizontal sides. Similarly the length of the left vertical side is equal to the combined length of the right two vertical sides. Because of this, you actually don't need to find the lengths of the unknown sides to answer the question.

This means the perimeter is:

$P=(31 \times 2)+(25 \times 2)\\P=62+50\\P=112$

Question 6:

Exactly the same process as above. Just double the longest vertical and horizontal sides (since the sum of the corresponding shorter sides is equal). You'll notice the longest horizontal side is 31, and the longest vertical side is 25...exactly the same as the previous question.

Therefore, the perimeter will again be 112 inches.

These two questions illustrate the difference between area and perimeter. Even though the perimeter of the two shapes is the same, the area of the second shape is larger than the area of the first.

3 0

4 years ago

Find the value of each variable for the right triangles. make sure all answers are in reduced radical form. show your work.

dimulka [17.4K]

That's how you find the value for x

3 0

3 years ago

Use long division to change 11/30 to a decimal

Angelina_Jolie [31]

Hope this helps! answer= 0.366 to 3 decimal places

4 0

3 years ago

Read 2 more answers

Use the confidence level and sample data to find a confidence interval for estimating the population μ. Round your answer to the

Levart [38]

Answer: Choice A.) 88.2 < μ < 93.0

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Explanation:

We have this given info:

n = 92 = sample size
xbar = 90.6 = sample mean
sigma = 8.9 = population standard deviation
C = 99% = confidence level

Because n > 30 and because we know sigma, this allows us to use the Z distribution (aka standard normal distribution).

At 99% confidence, the z critical value is roughly z = 2.576; use a reference sheet, table, or calculator to determine this.

The lower bound of the confidence interval (L) is roughly

L = xbar - z*sigma/sqrt(n)

L = 90.6 - 2.576*8.9/sqrt(92)

L = 88.209757568781

L = 88.2

The upper bound (U) of this confidence interval is roughly

U = xbar + z*sigma/sqrt(n)

U = 90.6 + 2.576*8.9/sqrt(92)

U = 92.990242431219

U = 93.0

Therefore, the confidence interval in the format (L, U) is approximately (88.2, 93.0)

When converted to L < μ < U format, then we get approximately 88.2 < μ < 93.0 which shows that the final answer is choice A.

We're 99% confident that the population mean mu is somewhere between 88.2 and 93.0

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3 years ago

Prove that√P is irrational for any prime number P

Luda [366]

Answer:

Step-by-step explanation:

I’m not sure if this is super accurate, but since P is prime, the only factors it has is 1 and itself, meaning that the square root of it will be irrational

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3 years ago