Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
Answer:
4x^2−1
Step-by-step explanation:
City code says you need to have a total of at least 54 toilet stalls, but each bathroom can only have 6 stalls.
So, Let the number of bathrooms to be built be = x
Number of toilet stalls needed = 54
Number of stalls each bathroom can have = 6
So, the number of bathrooms to be built are =
Hence, one must build 9 bathrooms with 6 stalls each.
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