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3 years ago

Do the gas laws apply to liquids ?

Chemistry

2 answers:

Contact [7]3 years ago

6 0

Answer:

The Ideal Gas Law cannot be applied to liquids. The Ideal Gas Law is #PV = nRT#. That implies that #V# is a variable. But we know that a liquid has a constant volume, so the Ideal Gas Law cannot apply to a liquid.

Explanation:

this is my awnser soory if it was a multiple choice question plz mark brainliest

tangare [24]3 years ago

3 0

the ideal gas law cannot be applied to liquids

the ideal gas law is PV= nRT

that implies that V is a variable. But we know that a liquid has a constant volume, so the Ideal Gas Law cannot apply to a liquid

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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

$PCl_3,p_1'=6.798 Torr$

$Cl_2,p_2'=26.398 Torr$

$PCl_5,p_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=p_1=13.2 Torr$

Partial pressure of the $Cl_2=p_2=13.2 Torr$

Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{p_1}{p_1\times p_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=p_1'+p_2'+p_3'$

$263.0Torr=13.2 Torr+p_2'+217.0 Torr$

$p_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

$p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

6 0

3 years ago

What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?

mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we convert 166.00 g of KI into moles, using its molar mass:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

166.00 g ÷ 166 g/mol = 1 mol KI

Then we calculate the required volume, using the definition of molarity:

Molarity = moles / liters

Liters = moles / molarity

1 mol / 1.00 M = 1 L

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3 years ago

Based off of the simulation pulley gizmo; how many people did it take to lift the armchair with a fixed pulley? (Look at Activit

DedPeter [7]

Answer:

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3 years ago

Which of the following is an example of a safe laboratory procedure?

ollegr [7]

A is the correct answer. Tying back long hair and loose clothing is important so they don’t dangle in flames or liquids that could dissolve or bleach them, for example. The other choices - consuming food and drink from lab wares, touching hot objects without gloves on and inhaling odors - are examples of very unsafe procedures.

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3 years ago

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Which of the following effect increases the solubility of Ca(OH)2?

mash [69]

Answer:

adding an acidic solution

Explanation:

Strong acids dissociate completely in water and the H⁺ ions react with the OH⁻ ions to make H₂O. If we add an acid to our solution of Ca(OH)₂, the acid protons would react with some of the OH⁻ ions and drive the equilibrium to the right. More of the solid Ca(OH)₂ should dissolve.

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3 years ago