Answer:
6.78 × 10⁵ J
Explanation:
Step 1: Given and required data
- Latent heat of vaporization of water (ΔH°vap): 2260 J/g
Step 2: Calculate the heat (Q) required to vaporize 300 grams of water
We will use the following expression.
Q = ΔH°vap × m
Q = 2260 J/g × 300 g
Q = 6.78 × 10⁵ J
6.78 × 10⁵ Joule will be required to convert 300 g of water to steam at 100 °C.
The answer is D. In the visible spectrum of light, ultraviolet light has the most energy while red has the least energy. Violet light has shorter wavelengths and higher frequency. This is converse to red light that has longer wavelengths but lower frequency.
Answer:
not sure but i guess it's Tellurium
Answer:
E = 17 kJ
Explanation:
The enthalpy of the reaction is:
<u>Where</u>:
Ep: is the energy of the products
Er: is the energy of the reactants
Similarly, the enthalpy of the reaction is related to the activation energy forward (
) and to the activation energy reverse (
) as follows:
Having that ΔH = 44 kJ and = 61 kJ, the activation energy of the reverse reaction is:
Therefore, the activation energy of the reverse reaction is 17 kJ.
I hope it helps you!
