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3 years ago

Write an equilibrium equation that shows bisulfate acting as a weak acid in water.

Chemistry

1 answer:

NemiM [27]3 years ago

4 0

Answer:

Explanation:

Bisulphate ion is a weak acid as it can form hydronium ion in water .

HSO₄⁻ + H₂O ⇄ SO₄⁻² + H₃O⁺

The equilibrium constant of this reaction is very small , hence bisulphate ion is very weak acid.

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Evgen [1.6K]

Answer:

It was called MANURE

Explanation:

Its a type of fertilizer which plant are ploughed back into the soil.

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3 years ago

Planet A is an inner planet with no moon and hardly any atmosphere. Planet B is an inner planet with no moon but with a dense at

postnew [5]

I think the answers are Mars and Venus

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3 years ago

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Mariana [72]

Answer:

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3 years ago

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Which statement best explains why calcium has a larger atomic radius than magnesium? A. Calcium has a stronger nuclear charge th

ahrayia [7]

Answer:

B. calcium has electrons in more energy levels than magnesium

Explanation:

atoms are made of three types of subatomic particles - electrons, protons and neutrons.

Neutrons and protons reside in the nucleus of the atom and electrons reside in energy shells

electronic configuration for both Ca and Mg are as follows

Mg - 2,8,2

Ca - 2,8,8,2

outermost energy shell of Mg with electrons is the third energy level

whereas outermost energy shell of Ca with electrons is the fourth energy shell

therefore Ca has a larger atomic radius than Mg as it has one more energy shell than Mg in which electrons reside

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3 years ago

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The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago